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kramer
3 years ago
8

a battery of 9v is connected in series with resistors of 0.2ohm , 0.3ohm, 0.5ohm, and 5 ohm respectively. how much current would

flow through a 5 ohm resistor.​
Physics
1 answer:
Nonamiya [84]3 years ago
5 0

Answer:

1.5 A

Explanation:

Applying

V = IR'....................... Equation 1

make I the subject of the equation

I = V/R'.................. Equation 2

Where V = Voltage, I = current, R' = Total resistance.

From the question,

In a series connection,

R' = 0.2+0.3+0.5+5 = 6 ohm.

Given: V = 9V

Substitute into equation 2

I = 9/6

I = 1.5 A.

Note: Since all the resistors are connected in series, thesame current flows through them

Therefore the current flowing through the 5 ohm resistor = 1.5 A

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Answer:

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Explanation:

given data

resister r = 5.80 kΩ

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solution

we get here I total

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so here power will be

power = I²×R    .............1

power = 2² ×  5.80

power = 23.2 mW

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Answer:

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