Answer:
4.75 m/s
Explanation:
The computation of the velocity of the existing water is shown below:
Data provided in the question
Tall = 2 m
Inside diameter tank = 2m
Hole opened = 10 cm
Bottom of the tank = 0.75 m
Based on the above information, first we have to determine the height which is
= 2 - 0.75 - 0.10
= 2 - 0.85
= 1.15 m
We assume the following things
1. Compressible flow
2. Stream line followed
Now applied the Bernoulli equation to section 1 and 2
So we get

where,
P_1 = P_2 = hydrostatic
z_1 = 0
z_2 = h
Now

= 4.7476 m/sec
= 4.75 m/s
To stop the car it would be 100m because if the car is going to 65km/h then it would still be 100km/h
Answer:
A. 20 N
Explanation:
the weight of book is 2×10= 20N
Answer:
350x^2
Explanation:
I'm assuming you're saying you're using them together, like stacking them on top of each other, so if that's the case then this is a simple multiplication problem, which can be written as 10x(35x). Solve it and you get 350x^2.
Explanation:
It is given that,
Spring constant of the spring, k = 475 N/m
Mass of the block, m = 2.5 kg
Elongation in the spring from equilibrium, x = 5.5 cm
(a) We know that the maximum elongation in the spring is called its amplitude. So, the amplitude for the resulting oscillation is 5.5 cm.
(b) Let
is the angular frequency. It is given by :



(c) Let T is the period. It is given by :


T = 0.45 s
(d) Frequency,


f = 2.23 Hz
(e) Let v is the maximum value of the block's velocity. It is given by :



The value of acceleration is given by :



Hence, this is the required solution.