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loris [4]
3 years ago
11

PLEASE HELP!!

Chemistry
1 answer:
Serga [27]3 years ago
7 0

Answer:

D. Pure gold

Explanation:

Hello,

In this case, since gold, as a heavy metal, is said to be less reactive than hydrogen, when it undergoes electrolysis process when forming a salt, due to the action of the electric current, we can appreciate the formation of a layer of gold on the surface of the cathode via a reduction half-reaction from gold (I) to metallic gold:

Au^++1e^-\rightarrow Au^0

Thereby, D. Pure gold is formed as the product of the reaction.

In contrast, more reactive metals than hydrogen such as sodium or potassium, will remain in solution so the hydrogen converted to hydrogen gas.

Best regards-

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Select all the correct statements, there is more than one.
alexgriva [62]

Answer:

Experiments to determine mechanisms involve looking at indirect evidence to help support or disprove a proposed mechanism.

Most intermediates are not typically isolated to determine reaction mechanisms.

Carbocations are very reactive and are typically not isolated for analysis.

Scientists can prove that a specific mechanism exists.

Evidence of intermediates sometimes can be seen using techniques such as nuclear magnetic resonance spectroscopy

Explanation:

The study of reaction mechanism and chemical kinetics often form the main thrust of study in organic, inorganic and physical chemistry.

We often want to know the actual processes involved in the conversion of one specie to another. Unfortunately, this information may have to be obtained indirectly by certain chemical reactions or by the use of new instrumental methods such as nuclear magnetic resonance spectroscopy.

Many organic reactions have carbocation intermediates. These carbocations are relatively short-lived and are transient intermediates which are rarely isolated unless they are isolated in a molecular cage using a macromolecule or in superacids.

By intensive study, scientists can proof or disprove the authenticity of any proposed mechanism.

We must know that a transition state has partial bonds. It is often an extremely short-lived specie which cannot be isolated.

4 0
3 years ago
12.<br>Contrast and compare:<br>a) ionic and covalent bonding​
Y_Kistochka [10]

Answer:

Ionic bonds - an intramolecular force exist in a nonmetal and metal compounds such as NaCl. The Na donate 1 electon to Cl to complete its octet rule.

Covalent bond - an intramolecular force exist in a nonmetal and nonmetal compounds such as bonds O2, Cl2, CO2, sugar, proteins and most of organic compounds and biomolecules by sharing electrons to bond.

There are two types of covalent bonds: polar and nonpolar. Polar bond is a bond between two different nonmetal atoms of different electronegativities. While nonpolar bond is a bond between the same atom or two differenct atoms of the same electronegativities (if there is). Their electronegativities pull will cancel so that their overall polarity is zero.

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3 years ago
A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spheric
Luba_88 [7]

Complete Question

A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spherical air tank that measures 74.0 wide. The biologist estimates she will need 2600 L of air for the dive. Calculate the pressure to which this volume of air must be compressed in order to fit into the air tank. Write your answer in atmospheres. Round your answer to significant digits.

Answer:

The pressure required is P_2= 12.2 \ atm

Explanation:

Generally the volume of a sphere is mathematically denoted as

             V_s = \frac{4}{3} * \pi r^3

Substituting r =  \frac{d}{2} = \frac{74}{2} = 37cm

          V_s = \frac{4}{3} * 3.42 * (37)^2

               V_s = 2.121746 *10^5 cm^3

Converting to Liters

               V_s = \frac{2.121746 *10^5}{1000}

                V_s= 212.1746L

Assume that the pressure at which the air is given to the diver is 1 atm when the air was occupying a volume of 2600L

So

From Charles law

               P_1V_1 = P_2 V_s

Substituting  V_1 =2600 L ,   P_1 = 1 atm , V_s  =212.1746L , and making P_2 the subject we have

                 P_2 = \frac{P_1 * V_1}{V_s}

                     = \frac{1 * 2600}{212.1746}

                    P_2= 12.2 atm

               

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MArishka [77]

Answer:

what are the items that have been listed?

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Answer:

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