Answer: The actual free-energy change for the reaction -8.64 kJ/mol.
Explanation:
The given reaction is as follows.
Fructose 1,6-bisphosphate 
Glyceraldehyde 3-phosphate + DHAP
For the given reaction, 
is 23.8 kJ/mol.
As we know that,
Here, R = 8.314 J/mol K, T = 
= (37 + 273) K
= 310.15 K
Fructose 1,6-bisphosphate = 
M
Glyceraldehyde 3-phosphate = 
M
DHAP = 
M
Expression for reaction quotient of this reaction is as follows.
Reaction quotient = ![\frac{[DHAP][\text{glyceraldehyde 3-phosphate}]}{[/text{Fructose 1,6-bisphosphate}]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BDHAP%5D%5B%5Ctext%7Bglyceraldehyde%203-phosphate%7D%5D%7D%7B%5B%2Ftext%7BFructose%201%2C6-bisphosphate%7D%5D%7D)
Q = 
= 
Now, we will calculate the value of 
as follows.
= 
= -8647.73 J/mol
= -8.64 kJ/mol
Thus, we can conclude that the actual free-energy change for the reaction -8.64 kJ/mol.
Answer: The amount of water formed is 12 moles
Explanation: Please see the attachments below
Answer:
See explanation
Explanation:
Carbon monoxide is toxic because it can successfully competes with oxygen for hemoglobin (Hb) sites according to the following equilibrium:
Hb(O₂)₄(aq) + 4CO(g) ⇄ Hb(CO)₄(aq) + 4O₂(g)
Based on LeChatelier’s Principle, CO poisoning can be reversed by applying O₂(g) to victim. This addition of O₂(g) increases system concentration of O₂(g) in the equilibrium reaction thereby overloading the product side of the equilibrium forcing it to shift to the left, decomposing the carboxyhemoglobin (Hb(CO)₄) and releasing the CO(g) and combining with O₂(g) to form more Hb(O₂)₄.
Sure Maybe its because when they react with water the form an alkali. For example NaOH - from sodium.
Answer:
Carbon has 6 electrons in the outside and 6 protons inside.
Explanation:
Carbon has a mass number A = 12 and an atomic number Z = 6. The latter means that the element has 6 protons inside and 6 electrons in the nucleus that neutralize said positive charge.
