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Elodia [21]
4 years ago
5

Solve |2x+3/4 |=5 1/2 Please help!!!!

Mathematics
1 answer:
Inga [223]4 years ago
5 0

Answer:

=2x+3/4=5.50

x=19/8 or 2 3/8

hope this helps

Step-by-step explanation:

You might be interested in
The base of a triangle is 5 45 cm and the height is 3 88 cm. What is the area of the triangle? Recall: A= 1 2 bh
galina1969 [7]

Answer:

i got 21.146

Step-by-step explanation:

multiply 5.45 x 3.88 and thats the answer. it may need to be rounded.

21.10?

3 0
3 years ago
On a map, 1/2 inch represents 10 actual miles. Two towns that are 4 1/2 inches apart on this map are how many actual miles apart
dusya [7]
The answer is E.90

1/2 inches = 10 miles
9(1/2) inches = 4 1/2 inches
9(10) miles = 90 miles
7 0
3 years ago
Solve the equation s + 2.8 = 6.59
Contact [7]
S + 2.8 = 6.59
s = ?

To solve for s use the inverse operation of addition, which is subtraction.

s + 2.8 = 6.59
6.59 - 2.8 = s
6.59 - 2.8 = 3.79
s = 3.79

Check:

s + 2.8 = 6.59
s = 3.79
3.79 + 2.8 = ?
3.79 + 2.8 = 6.59
Correct!

This proves: s = 3.79 ;)
6 0
3 years ago
Read 2 more answers
A poll is given, showing 60% are in favor of a new building project.
nikdorinn [45]

Answer:

+70%

Step-by-step explanation:

as more than 7 people wants the building so the probability is 70%

hope it helps you

please mark me as brainlist

6 0
3 years ago
Please answer right away!!!
liraira [26]

Answer:

22.9m

Step-by-step explanation:

Using Pythagorean theorem, we can get two equations using the angles.

From Point A:

∠A = 20°

AB = 20m

From Point B:

∠B = 29°

BD = x

What we are looking for is the opposite side of each right triangle, each person makes because we have one adjacent side. We also know that both opposite sides will be equal.

So we use this formula for both point of views:

Tan\theta=\dfrac{Opposite}{adjacent}

Where:

Opposite = height of the building

Adjacent = distance from the building

We are looking for the opposite side so we can tweak our formula to get an equation for the height

height=(Tan\theta)(distance)

Using our given, we can solve for the distance of point B to D:

(Tan20)(20+x) = (Tan29)(x)\\\\(0.3640)(20+x) = (0.5543)(x)\\\\\dfrac{(7.28+0.3640x)}{0.5543}=x\\\\13.1337 + 0.6567x = x\\\\13.1337 = x - 0.6567x\\\\13.1337 = 0.3433x\\\\\dfrac{13.1337}{0.3433}=x\\\\38.2572 = x

The distance of point B to D is 38.2572 m.

Now that we know the distance of BD we can solve for the height of the building using only the given from point B.

height=(Tan\theta)(distance)

height=(Tan29)(38.2572m)

height=(0.5543)(38.2572m)

height=21.21m

But this is only the height from the line of sight. To get the height of the building from the ground, we just add the height of the viewer, which is 1.7m.

21.21m + 1.7m = 22.91m

The closest answer is: 22.91 m

8 0
4 years ago
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