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Jet001 [13]
2 years ago
8

What is the product of the complex numbers 3 - 4iand 6+i where i= -1

Mathematics
2 answers:
Nadusha1986 [10]2 years ago
8 0

Answer:

Step-by-step explanation:

(3-4 \iota)(6+\iota)\\=18+3 \iota-24 \iota-4 \iota^2\\=18-21 \iota+4\\=22-21 \iota

mixas84 [53]2 years ago
5 0

Answer:

35

Step-by-step explanation:

Since i=-1, we can rewrite the equation as 3-[4(-1)} multiplied by 6+(-1). Since

4 x-1=, 3-(-4)=7. 6-1=5, and 7x5=35.

You might be interested in
Find the greatest common factor 28 and 12<br><br> use the GCF to factor 28+12.
fgiga [73]

Answer:

(a) 4

(b) 4 * (7+3)

Step-by-step explanation:

(a) Let's first start by prime factorizing (finding the prime factors) 28 and 12:

12: 2*2*3

28: 2*2*7

We can see here they both share a common factor of 2*2, which is 4, therefore the GCF is 4.

(b) Factor a 4 out from the equation:

4*(\frac{28}{4}+\frac{12}{4})

This gives us:

4 * (7+3)

5 0
2 years ago
A scientist needs 4.8 liters of a 12% alcohol solution. She has available a 22% and a 10% solution. How many liters of the 22% a
yanalaym [24]

Answer:

  • 4.0 L of 10%
  • 0.8 L of 22%

Step-by-step explanation:

For mixture problems, it is convenient to define a variable to represent the amount of the greatest contributor. Let x represent the amount of 22% solution in the mix. Then 4.8-x is the amount of 10% solution.

The amount of alcohol in the mix is ...

  0.22x +0.10(4.8-x) = 0.12(4.8)

Eliminating parentheses, we have ...

  0.22x -0.10x +0.10(4.8) = 0.12(4.8)

Subtracting (0.10)(4.8) and combining x-terms gives ...

  0.12x = 0.02(4.8)

  x = (0.02/0.12)(4.8) = 0.8 . . . . . divide by the x-coefficient

The scientist needs 0.8 L of 22% solution and 4.0 L of 10% solution.

5 0
3 years ago
What is the equation of the line that is parallel to the
Blababa [14]

Answer:

';

lk;j

Step-by-step explanation:

uhh

4 0
2 years ago
Please help, math question.
Veseljchak [2.6K]
Part a) 
Identify the variable and categories


By reading the above statement, we can find that there are two variables and each variable has 2 categories. The variables and their categories are:
1) Class Number
This variable is further divided into 2 categories i.e. Class 9th and Class 10th.

2) Participation in Extracurricular activities
This variable is further divided into 2 categories based on if students participated or not.

Part b)
Set up and fill 2 way table.

Since, we have 2 variables and each variable has 2 categories the number of data cells will be 2 x 2 = 4 cells

There are total 100 students. 40 students are in class 10th. This means 60 students are in class 9th.Out of 40 students in class 10th, 18 students participate in at least one extracurricular activity. So remaining 22 students do not participate. 32 students from class 9th participate in extracurricular activities, this means the remaining 28 students do not participate. Based on this data, we can fill up the table as shown below
 

6 0
3 years ago
6.
larisa86 [58]

A. Every month Population will increase by a factor of 0.84%.

B.  Every 3 months Population will increase by a factor of 2.5%.

C. Increase in population in every 20 months is 10% + 6.72% = 16.72%.

<u>Step-by-step explanation:</u>

Here, we have  number of employees in a company has been growing exponentially by 10% each year. So , If we have population as x in year 2019 , an increase of 10% in population in 2020 as  x + \frac{x}{100}\times10 which is equivalent to \frac{11x}{10}.

<u>A.</u>

For each month: We have 12 months in a year and so, distributing 10% in 12 months would be like \frac{10}{12}  = 0.84 . ∴ Every month Population will increase by a factor of 0.84%.

<u>B.</u>

In every 3 months: We have , 12 months in a year , in order to check for every 3 months  \frac{12}{3} = 4 and Now, Population increase in every 3 months is \frac{10}{4}  = 2.5.  ∴ Every 3 months Population will increase by a factor of 2.5%.

<u>C.</u>

In every 20 months: We have , 12 months in a year in which increase in population is 10% . Left number of moths for which we have to calculate factor of increase in population is 20-12 = 8. For 1 month , there is 0.84% increase in population ∴ For 8 months , 8 × 0.84 = 6.72 %.

So , increase in population in every 20 months is 10% + 6.72% = 16.72%.

5 0
3 years ago
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