Answer:
In half it would go twice as far but the effect of lost kinetic energy is lessened.( I could be wrong)
Answer:
Explanation:
Given parameters:
pH of HNO₃ = 3.75
Unknown:
[OH⁻], concentration of hydroxyl ions = ?
pOH of the solution = ?
Solution
The pH or pOH scale is a convenient way of expressing the level of acidity or alkalinity of aqueous solutions.
The pH of a solution is the negative logarithm to base 10 of the hydrogen ion concentration of the solution:
pH = -log₁₀[H⁺]
pOH = -log₁₀[OH⁻]
For any aqueous solution, the sum of the pH and pOH is 14. That is;
pH + pOH = 14
Now solving for [OH⁻]:
HNO₃ + H₂O → H₃O⁺ + NO₃⁻
Since pH + pOH = 14
pOH = 14 - pH = 14 -3.75 = 10.25
since pOH = -log₁₀[OH⁻]
10.25 = -log₁₀(OH⁻)
[OH⁻] = inverse log₁₀(-pOH)
[OH⁻] = inverse log₁₀(-10.25) = 5.62 x 10⁻¹¹moldm⁻³
Answer:
C₂H₂(g) + 2.5 O₂(g) ⇒ 2 CO₂(g) + H₂O(l) ΔH° = -1300 kJ/mol
Explanation:
In the combustion of acetylene, it reacts with oxygen to produce carbon dioxide and water. The corresponding chemical equation is:
C₂H₂(g) + 2.5 O₂(g) ⇒ 2 CO₂(g) + H₂O(l)
The thermochemical equation includes the balanced chemical equation, stating the states of aggregation and the enthalpy of the reaction.
C₂H₂(g) + 2.5 O₂(g) ⇒ 2 CO₂(g) + H₂O(l) ΔH° = -1300 kJ/mol
Answer:
Br⁻, Be²⁺, Li⁺ , O²⁻, N³⁻
Explanation:
Ions are formed when an atom lose or gain the electrons.
There are two types of ions.
Cations and anions
Cations:
When an atom lose the electron cations are formed and atom gain positive charge.
X → X⁺ + 1e⁻
Anion:
When an atom gain electron anion is formed and atom gain negative charge,
X + 1e⁻ → X⁻
In given list of elements Li and Be form positive ions because they easily lose their valance electrons.
Li → Li⁺ + 1e⁻
Be → Be²⁺ + 2e⁻
While oxygen, nitrogen and bromine gain the electrons easily to complete the octet and form negative ions.
Br + 1e⁻ → Br⁻
O + 2e⁻ → O²⁻
N + 3e⁻ → N³⁻
The answer is: H₃PO₄.
A phosphoric acid is three protic acid, which means that in water release tree protons.
Phosphoric acid ionizes in three steps in water.
First step: H₃PO₄(aq) ⇄ H₂PO₄⁻(aq) + H⁺(aq).
Second step: H₂PO₄⁻(aq)⇄ HPO₄²⁻(aq) + H⁺(aq).
Third step: HPO₄²⁻(aq) ⇄ PO₄³⁻(aq) + H⁺(aq).
Species that are present: H₃PO₄, H₂PO₄⁻, HPO₄²⁻, PO₄³⁻ and H⁺.
A buffer can be defined as a substance that prevents the pH of a solution from changing by either releasing or absorbing H⁺ in a solution.
Buffer is a solution that can resist pH change upon the addition of an acidic or basic components and it is able to neutralize small amounts of added acid or base, pH of the solution is relatively stable.