Answer:
1) not so long (maybe an hour or two)
2) access to information through the internet will be most affected if my computer and mobile phone run out of battery power.
3) yes, one should prepare for power outage. This can be done by having a standby alternative source of power like the use of inverters that stores electrical energy in form of chemical energy, and small internal combustion engine powered electric generators.
4) solar panels can be used to draw power from incident sun rays, this power can be stored in an inverter for future use in case of a power outage.
5) energy from the sun is converted into direct current which is then supplied to an accumulator in the opposite direction to its flow of current. When the energy is needed, it can be used directly, or converted to an alternating current. This is achieved by connecting its terminal to the supply. Electric field is generated by flow of ions and electrons within the working chemical (e.g lithium).
Explanation:
D. The osculations show a variable rate of motion. Hope this helps:)
Answer:
<h2>
The magnitude of the magnetic is 0.145 T</h2>
Explanation:
Given :
Speed of proton 
Mass of proton 
Kg
The force on the proton in magnetic field is given by,
But 
(∵ Force is perpendicular to the velocity so 
)
When particle enter in magnetic field at the angle of 90° so particle moves in circle
So force is given by,
Where 
radius but in our case 0.23 m, 
C
By comparing above two equation,
T
Answer:
Reset
Explanation:
Digital methods are the methods that are uses methodological outlook to study societal change and cultural condition of online data. Reset is use to disguise data In digital methods. It is use to set again and conceal data by giving the data a different form. It restores the device to the original manufacture's settings.
Answer:
P = 0.25 W
Explanation:
Given that,
The emf of the battry, E = 2 V
The resistance of a bulb, R = 16 ohms
We need to find the power delivered to the bulb. We know that, the formula for the power delivered is given by :
So, 0.25 W power is delivered to the bulb.
