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How high would you have to go in the atmosphere for half of the mass of air to be below you?

1 answer:

6 0

5.6 km exact height of the atmosphere has no real meaning, air progressively gets thinner and thinner the higher one travels upwards

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Two workers are sliding 290 kg crate across the floor. One worker pushes forward on the crate with a force of 430 N while the ot

m_a_m_a [10]

Answer:0.27

Explanation:

Given

One worker Pushes with force $F_1=430 N$

other Pulls it with a rope of rope $F_2=360 N$

mass of crate $m=290 kg$

both forces are horizontal and crate slides with a constant speed

Both forces are in the same direction so Friction will oppose the forces and will be equal in magnitude of sum of two forces because crate is moving with constant speed i.e. net force is zero on it

$f_r=F_1+F_2$

where $f_r$ is the friction force

$f_r=430+360$

$f_r=790 N$

$f_r=\mu N$

where $\mu$ is the coefficient of static friction

$N=mg$

$790=\mu 29\cdot 9.8$

$\mu =0.27$

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Two small children decide it would be fun to toss a couple of large cats at each other. Cat A (7kg) is thrown at 7m/s and cat B

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Answer:

V=4.7m/s

Explanations:

Let Ma mass of cat A=7kg

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Mb mass of cat b=6.1kg

VB velocity of cat b=2m/s

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MaVa+MbVb=(Ma+Mb)V

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61.2=13.1V

V=4.7m/s

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