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galina1969 [7]
4 years ago
9

A powerful storm attacks the coast, with winds blowing at 89 miles per hour. what is the velocity of these winds?

Physics
2 answers:
PtichkaEL [24]4 years ago
6 0
Let's convert the speed of the winds into SI units.
We know that
1 miles = 1609 m
1 hour = 3600 s
So, the velocity written in m/s is
v=89  \frac{miles}{h} =89  \frac{miles}{h} \cdot  \frac{1609 m/miles}{3600 s/h}=39.8 m/s
Anarel [89]4 years ago
6 0

Answer: There is not enough information to answer the question.

Explanation: The rate of the coastal wind is called speed and its measured in mile per hour.

No information for calculating the velocity.

No distance travelled by the wind and time taken in any specific period.

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How do determine which is Y2, Y1, X2, and X1 on a graph. <br><br> And how do find rise over run.
fredd [130]
One point will be X1,Y1 and the other will be X2,Y2. It does not matter which is which except that X1 and Y1 have to be the same point and X2 and Y2 have to be the same point. For example, let's say you were given (2,3) and (6,8). No matter which point is X1,Y1 and the other is X2,Y2, the slope will still be 5/4. 

The rise is the change in y from one point to the other. The run would be the change in x from one point to the other.
7 0
4 years ago
Describe what has happened when a player "fumbles" the ball. (American Football)
Nesterboy [21]

Answer:

The players drops the ball either do to contact, the ball being stripped or personal error

Explanation:

6 0
3 years ago
A 600-nm-wavelength beam of light is incident on a soap film with air on both sides. The film has an index of refraction of 1.33
sergiy2304 [10]

Answer:

the film's minimum thickness to make the reflected light enhanced in brightness is 112.8 nm

Explanation:

Given the data in the question;

wavelength λ = 600 nm  

index of refraction = 1.33

so the film's minimum thickness to make the reflected light enhanced in brightness = ?

condition for maxima for reflected light is;

2nt = [ ( 2m + 1 )λ ] / 2

we solve for t

4nt = [ ( 2m + 1 )λ ]

t =  [ ( 2m + 1 )λ ] / nt

Now, for minimum thickness m = 1

t = λ / 4n

so we substitute in our values;

t = 600 nm / ( 4 × 1.33 )

t = 600 nm / 5.32

t = 112.78195 ≈ 112.8 nm  { one decimal place }

Therefore, the film's minimum thickness to make the reflected light enhanced in brightness is 112.8 nm

4 0
3 years ago
Please help..................​
worty [1.4K]

Answer:

PART A

In a solid

The attractive forces keep the particles together tightly enough so that the particles do not move past each other. ... In the solid the particles vibrate in place. Liquid – In a liquid, particles will flow or glide over one another, but stay toward the bottom of the container.

In a liquid

Particles are quite close together and move with random motion throughout the container. Particles move rapidly in all directions but collide with each other more frequently than in gases due to shorter distances between particles.

A gas

The particles move rapidly in all directions, frequently colliding with each other and the side of the container. With an increase in temperature, the particles gain kinetic energy and move faster.

PART B

The molecules are continually colliding with each other and with the walls of the container. When a molecule collides with the wall, they exert small force on the wall The pressure exerted by the gas is due to the sum of all these collision forces. The more particles that hit the walls, the higher the pressure.

Explanation:

GOOD LUCK!!! :)

7 0
3 years ago
A book light has a 1.4 W, 4.8 V bulb that is powered by a transformer connected to a 120 V electric outlet. The secondary coil o
VLD [36.1K]

Answer:

Turns of the primary coil: 500

Current in the primary coil: Ip= 0.01168A

Explanation:

Considering an ideal transformer I can propose the following equations:

        Vp×Ip=Vs×Is

Vp= primary voltaje

Ip= primary current

Vs= secondary voltaje

Is= secondary current

        Np×Vs=Ns×Vp

Np= turns of primary coil

Ns= turns of secondary coil

From these equations I can clear the number of turns of the primary coil:

Np= (Ns×Vp)/Vp = (20×120V)/4.8V = 500 turns

To determine the current in the secondary coil I use the following equation:

Is= (1.4W)/4.8V = 0.292A

Therefore I can determine the current in the primary coil with the following equation:

Ip= (Vs×Is)/Vp = (4.8V×0.292A)/120V = 0.01168A

5 0
3 years ago
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