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Levart [38]
3 years ago
10

How many energy levels does period 5 and period 6 have?

Chemistry
1 answer:
creativ13 [48]3 years ago
3 0
Period 5 has 5 energy levels and Period 6 has 6 energy levels
You might be interested in
Upon decomposition, one sample of magnesium fluoride produced 2.15 kg of magnesium and 3.36 kg of fluorine. A second sample prod
Eva8 [605]

Answer:

The second sample will produce 1563 grams of fluorine (F2)

Explanation:

The reaction will be MgF2 → Mg + F2

The stoichiometry ratio of MgF2 and F2 is 1 : 1.

That means for 1 mole of MgF2 consumed there is 1 mole of F2 produced.

The first sample produces 2.15 kg of magnesium and 3.36 kg of fluorine

The second sample produced 1 kg of magnesium and x kg of fluorine

This we can show in the following equation =

2.15kg / 3.36 kg = 1kg / x

2.15/3.36 = 0.63988

0.63988 = 1/ x

x= 1/0.63988  = 1.563 kg

1.563kg = 1563 grams

The second sample will produce 1563 grams of fluorine (F2)

8 0
3 years ago
if 200.0 of copper (II) sulfate react with an excess of zinc metal, what is the theoretical yield of copper?
kobusy [5.1K]
79.63 grams, hope this helps! 
7 0
3 years ago
Someone please help me with this
igor_vitrenko [27]

Answer:

I think A should be the answer because oxygen is the chemical change of carbon.

7 0
3 years ago
Help me out please an thank you
ivanzaharov [21]
The second one, I could be mistaken though
3 0
3 years ago
Nitrate salts (NO3), when heated, can produce nitrites (NO2) plus oxygen (O2). A sample of potassium nitrate is heated, and the
Lostsunrise [7]

Answer: a) 0.070 moles of oxygen were produced.

b) New pressure due to the oxygen gas is 2.4 atm

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 2.7 atm

V = Volume of gas = 700 ml = 0.7 L

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature = 329 K

n=\frac{PV}{RT}

n=\frac{2.7atm\times 0.7L}{0.0821 L atm/K mol\times 329K}=0.070moles

Thus 0.070 moles of oxygen were produced.

When the 700 mL flask cools to a temperature of 293K.

PV=nRT

P=\frac{nRT}{V}

P=\frac{0.070\times 0.0821\times 293}{0.7}

P=2.4atm

The new pressure due to the oxygen gas is 2.4 atm

7 0
4 years ago
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