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MrMuchimi
3 years ago
5

The following table shows the symptoms in four patients. Each patient suffers from a different disease.

Chemistry
2 answers:
RideAnS [48]3 years ago
6 0

Answer:

D.  Food poisoning, Bacteria Vomiting, loose stools

ryzh [129]3 years ago
5 0
I’d say D.

I was tempted on C but then I remembered that food poisoning is often caused by an infectious disease and the presence of bacteria in the stomach accompanied by vomiting and loose stools (also caused by bacteria presence in gut).

Hope this helped!
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The depletion of ozone (O3) in the stratosphere has been a matter of great concern among scientists in recent years. It is belie
gayaneshka [121]

Answer: 0.736 g

Explanation:

O_3+NO\rightarrow O_2+NO2

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of}O_3=\frac{0.781g}{48g/mol}=0.016moles

\text{Number of moles of}NO=\frac{0.589g}{30g/mol}=0.019moles

By Stoichiometry:

1 mole of ozone O_3 reacts with 1 mole of nitric oxide NO to form 1 mole of nitrogen dioxide NO_2

0.016 moles of ozone reacts with=\frac{1}{1}\times 0.016=0.016moles of nitric oxide to form 0.016 mole of NO_2

Thus ozone is the limiting reagent as it limits the formation of products and nitric oxide is the excess reagent as (0.019-0.016) g= 0.003 g remains as such.

Mass of NO_2=moles\times {\text{Molar mass}}=0.016\times 46=0.736g

0.736 g of NO_2 will be produced.

5 0
4 years ago
The spontaneous decay of an atom is called
Sladkaya [172]
The spontaneous decay of an atom is called transmutation 
5 0
4 years ago
Read 2 more answers
What volume would be occupied by 4.8 g of oxygen gas at 0.50 atm and 133°C? Hint: Determine moles of oxygen gas first.
Readme [11.4K]
Answer will be 1.24 atm
4 0
3 years ago
A. In the complete reaction of 22.99 g of sodium
fenix001 [56]

Answer : 58.44 g

<h3>Further explanation</h3>

The reaction

\tt Na+Cl\Rightarrow NaCl

mole ratio :

Na : Cl : NaCl = 1 : 1 : 1

Molar mass of Na : 22,989769 g/mol = 22.99 g/mol

Molar mass of Cl : 35,453 g/mol= 35.45 g/mol

Molar mass of NaCl : 58,44 g/mol

Let's check the mol for reactant (Na and Cl) and product(NaCl)

  • mol of Na :

\tt mol=\dfrac{22.99}{22.99}=1

  • mol of Cl :

\tt mol=\dfrac{35.45}{35.45}=1

Then the reactants are completed reacting because it matches the mole ratio, which is 1: 1

so that the mole of the product can be determined from the mol Na or Cl, which is 1

  • mass of NaCl :

\tt =\dfrac{mol~NaCl}{mol~Na}\times MW~NaCl\\\\=\dfrac{1}{1}\times 58.44\\\\=\boxed{\bold{58.44~g}}

3 0
4 years ago
I need help with this can someone please help me
Anna [14]
Sure, how can I help?
8 0
3 years ago
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