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4 years ago

In order to change grams of a substance to moles of the same substance, or vice versa, the following should be used:

Chemistry

2 answers:

Cerrena [4.2K]4 years ago

5 0

The answer would be C) molar mass

Inga [223]4 years ago

4 0

Answer:

C) molar mass

Explanation:

Hello,

In the calculations in chemistry, one of the major computations involve the conversion from mass to mole considering that there is no equipment that allows us to measure the exact moles of a substance since it depends on the type of atom, in spite of this fact, balances have been widely used to measure a substance's mass. In such a way, it is possible to relate them via the molar mass since it relates how many grams of a substance are contained in one mole of such substance. For instance, one mole of sodium chloride has 58.44 grams of sodium chloride or vice versa, so its molar mass is $58.44 g/mol$ .

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Calculate the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L.

Aleonysh [2.5K]

Answer: $15.5^0C$

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 0.987 atm

V = Volume of gas = 12 L

n = number of moles = 0.50

R = gas constant = $0.0821Latm/Kmol$

T =temperature = ?

$T=\frac{PV}{nR}$

$T=\frac{0.987atm\times 12L}{0.0820 L atm/K mol\times 0.50mol}=288.5K=(288.5-273)^0C=15.5^0C$

Thus the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L is $15.5^0C$

8 0

3 years ago

How many grams of carbon dioxide will form if 5.5 g of C3H8 burns in 15 g of O2?

mr Goodwill [35]

C3H8+3O2--->3CO2+8H
Therefore for every 1:3 there are 3 Carbon dioxides that form. That means find the limiting reactant from the two reactants.
5.5g(1mole C3H8/44.03g of C3H8)=0.1249 moled of C3H8 and if for every one C3H8 we can form three CO2. We can assume 0.3747 miles of CO2 will be produced.
15g of O2(1 mole O2/32g of O2)=0.4685moles O2 and if for every three O2 we can produce three CO2 we may assume a 1:1 ratio.
This means C3H8 will be your limiting reactant. Therefore 0.3747 moles of CO2 will be produced.
0.3747 moles of CO2(48.01 g of CO2/1 mole of CO2)= 17.99 grams of CO2

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4 years ago

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Answer:

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Explanation:

5.50 / 2.954 = x / 4.325

x = 8.05

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