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lukranit [14]
4 years ago
15

What is the force on an object due to its mass and gravity called?

Physics
1 answer:
DIA [1.3K]4 years ago
5 0

Answer:

The Gravitational force.

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4 years ago
a traffic light at an intersection is hanging from two wires of equal length making angles of 10 degrees below the horitzontal.
aleksandrvk [35]

The tensions in the wires at the given angle of inclination is determined as 434.1 N.

<h3>Tension on the wire</h3>

The tension in the wires is calculated as follows;

T = Wsinθ

where;

  • T is tension in each wire
  • W is weight of the traffic light

T = 2500 x sin(10)

T = 434.1 N

Thus, the tensions in the wires at the given angle of inclination is determined as 434.1 N.

Learn more about tension here: brainly.com/question/918617

#SPJ1

3 0
2 years ago
I.Solve the following problems and answer the following questions. Show all your work and provide answers rounded off to the app
Ilia_Sergeevich [38]

The sprinter’s average acceleration is 1.98 m/s²

The given parameters;

  • initial velocity of the sprinter, u = 18 km/h
  • final velocity of the sprinter, v = 27 km/h
  • time of motion of the sprinter, t = 3.5 x 10⁻⁴ h

Convert the velocity of the sprinter to m/s;

initial \ velocity, u = 18 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 5 \ m/s\\\\final \ velocity, v =27 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 7.5 \ m/s\\\\

The time of motion is seconds;

t = 3.5 \times 10^{-4} \ h \times \frac{3600 \ s}{1 \ h} = 1.26 \ s

The sprinter’s average acceleration is calculated as follows;

a = \frac{v- u}{t} \\\\a = \frac{7.5 \ m/s \ - \ 5 \ m/s}{1.26 \ s} \\\\a = 1.98 \ m/s^2

Thus, the sprinter’s average acceleration is 1.98 m/s²

Learn more here:brainly.com/question/17280180

6 0
3 years ago
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