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frozen [14]
3 years ago
9

I.Solve the following problems and answer the following questions. Show all your work and provide answers rounded off to the app

ropriate number of significant digits. Explain your reasoning when required in a maximum of a 5 lines paragraph.
1.During a race, a sprinter increases from 18 km/h to 27 km/h over a period of 3.5 X 10-4 h. What is the sprinter’s average acceleration in m/s2 during this period?
Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0

The sprinter’s average acceleration is 1.98 m/s²

The given parameters;

  • initial velocity of the sprinter, u = 18 km/h
  • final velocity of the sprinter, v = 27 km/h
  • time of motion of the sprinter, t = 3.5 x 10⁻⁴ h

Convert the velocity of the sprinter to m/s;

initial \ velocity, u = 18 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 5 \ m/s\\\\final \ velocity, v =27 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 7.5 \ m/s\\\\

The time of motion is seconds;

t = 3.5 \times 10^{-4} \ h \times \frac{3600 \ s}{1 \ h} = 1.26 \ s

The sprinter’s average acceleration is calculated as follows;

a = \frac{v- u}{t} \\\\a = \frac{7.5 \ m/s \ - \ 5 \ m/s}{1.26 \ s} \\\\a = 1.98 \ m/s^2

Thus, the sprinter’s average acceleration is 1.98 m/s²

Learn more here:brainly.com/question/17280180

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A small bug is lying resting when nine ants simultaneously ambush it and begin pulling it in different directions. They are each
xxMikexx [17]

Answer: The bug will remain motionless

Explanation:

According to Newton's first Law of Motion (sometimes called Law of Inertia):

<em>An object at rest or describing a uniform straight line motion (moving at constant velocity), will remain at rest or moving unless an external force is applied to it and changes its state of rest or motion. </em>

In other words:

An object or body will keep its state of motion until an external force changes its state

This means that objects tend to remain in its state of motion, and is the definition of the inertia, as well.

In addition, according to his law, an object in rest can be in equilibrium (net force equals to zero), and a moving object can also be in equilibrium, as long as it keeps a constant velocity.

<h2>This is why the bug, which is at rest will remain at rest, although the ants are simultaneously pulling it in different directions, since the resultant of all these forces is zero.</h2>
4 0
3 years ago
If jack was traveling at 100 miles in 2 hours what was his velocity in miles per second​
arsen [322]

1 hour is 3600 seconds. In 2 hours, it would be 7200 seconds.  Divide the amount of miles by seconds. 100/7200=.01388..

6 0
3 years ago
Read 2 more answers
A constant magnetic flux through a closed loop of wire induces an emf in that loop. True or false?
miskamm [114]

Answer: False

Explanation: In order to explain this problem we have to use the Faraday law, which say

dФm/dt=-ε  it means that the variation of the magnetic field flux with time is equal to the emf ( electromotive force). In our case the magnetic flux is constant then there is not a emf induced in a wire closed loop.

6 0
3 years ago
What information do we know about the known exoplanets? a. estimates of orbits and masses b. complete composition c. precise mas
LenKa [72]

<em>The correct option is </em><em>A</em>. The information we know about the known exoplanets is estimates of orbits and masses.

<h3>What is exoplanets?</h3>

An exoplanet or extrasolar planet is a planet outside the Solar System.

In other words, exoplanet is any planet beyond our solar system.

<h3>Characteristics of exoplanets</h3>

exoplanets are known for the following characteristics;

  • they are usually hot
  • they can orbit their stars so tightly that a “year” lasts only a few days
  • they can orbit two suns at once

Thus, the information we know about the known exoplanets is estimates of orbits and masses.

Learn more about exoplanets here: brainly.com/question/1514493

#SPJ1

5 0
2 years ago
Relative formula mass of CuCO3
Elodia [21]

AnMolar mass of CuCO3 = 123.5549 g/mol

This compound is also known as Copper(II) Carbonate.

Convert grams CuCO3 to moles  or  moles CuCO3 to grams

Molecular weight calculation:

63.546 + 12.0107 + 15.9994*3

Percent composition by element

Element   Symbol   Atomic Mass   # of Atoms   Mass Percent

Copper Cu 63.546 1 51.431%

Carbon C 12.0107 1 9.721%

Oxygen O 15.9994 3 38.848%

Explanation:

5 0
2 years ago
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