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frozen [14]
3 years ago
9

I.Solve the following problems and answer the following questions. Show all your work and provide answers rounded off to the app

ropriate number of significant digits. Explain your reasoning when required in a maximum of a 5 lines paragraph.
1.During a race, a sprinter increases from 18 km/h to 27 km/h over a period of 3.5 X 10-4 h. What is the sprinter’s average acceleration in m/s2 during this period?
Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0

The sprinter’s average acceleration is 1.98 m/s²

The given parameters;

  • initial velocity of the sprinter, u = 18 km/h
  • final velocity of the sprinter, v = 27 km/h
  • time of motion of the sprinter, t = 3.5 x 10⁻⁴ h

Convert the velocity of the sprinter to m/s;

initial \ velocity, u = 18 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 5 \ m/s\\\\final \ velocity, v =27 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 7.5 \ m/s\\\\

The time of motion is seconds;

t = 3.5 \times 10^{-4} \ h \times \frac{3600 \ s}{1 \ h} = 1.26 \ s

The sprinter’s average acceleration is calculated as follows;

a = \frac{v- u}{t} \\\\a = \frac{7.5 \ m/s \ - \ 5 \ m/s}{1.26 \ s} \\\\a = 1.98 \ m/s^2

Thus, the sprinter’s average acceleration is 1.98 m/s²

Learn more here:brainly.com/question/17280180

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Rainbow [258]

By Newton's second law, the apparent weight of rider coming at rest is <u>3548 N</u>.

According to formula, v = u + at

a = 39.2 m/s^{2}

Force, F = ma

F = m(a+g)

F = apparent weight

m = mass, given = 65 kg

a = acceleration, given = 39.2 m/s^{2}

g = 9.8 m/s^{2}

Put these values in formula, F = m(a+g)

F = 65(39.2+9.8)

F = 3548 N

Therefore, the apparent weight of rider coming at rest is <u>3548 N</u>.

Learn more about apparent weight here:- brainly.com/question/24897276

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