Answer:
The frequency of the tuning is 1.065 kHz
Explanation:
Given that,
Length of tube = 40 cm
We need to calculate the difference between each of the lengths
Using formula for length
For an open-open tube,
We need to calculate the fundamental wavelength
Using formula of wavelength
Put the value into the formula
We need to calculate the frequency of the tuning
Using formula of frequency
Put the value into the formula
Hence, The frequency of the tuning is 1.065 kHz
Answer:
t1 = t2 + 3.02 V = 41.5
V t1 - 1/2 g t1^2 = V t2 - 1/2 g t2^2
Both stones reach the same height after the specified times
V (t1 - t2) = g/2 (t1^2 - t2^2) = g/2 (t1 - t2) (t1 + t2)
2 V / g = t1 + t2 = 2t1 + 3.02
t1 = V / g - 1.51 = 41.5 / 9.8 -1.51 = 2.72 s
t2 = t1 + 3.02 = 5.74 sec
Check:
41.5 * 2.72 - 4.9 * 2.72^2 = 76.6 m
41.5 * 5.74 - 4.9 * 5.74^2 = 76.8 m
Speed of second stone = 41.5 - 9.8 * 2.72 = 14.8 m/s
Answer:
It would be the brick since the mass and the weight is greater than the peanut I might be wrong on this but thats the best answer i can give
Explanation:
The dependent variable was the time and the independent variable was thecars
Answer:
100 V
Explanation:
Hi there!
Ohm's law states that 
where V is the voltage, I is the current and R is the resistance.
Plug the given information into Ohm's law (R=50, I=A)
Therefore, the voltage across this current is 100 V.
I hope this helps!
