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Nutka1998 [239]
3 years ago
10

How did the invention of movable type change society?

Physics
1 answer:
alexdok [17]3 years ago
5 0
The moveable type drastically changed society. Its primary impact was the distribution of knowledge. Since people could now type books, rather than handwriting then, literary works could be shared faster than ever before. This had a massive impact on education.
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Which of the following statements does NOT accurately describe the Berlin Airlift?
Karo-lina-s [1.5K]

The Berlin Airlift is best described as the aircraft used to delivered needed food and supplies to the city of Berlin through the air because all other routes were blocked by the Soviet Union.

<h3>What is Berlin Airlift?</h3>

The Berlin airlift was a 1940s military operation that supplied West Berlin with food and other vital goods by air after the Soviet Union blockaded the city.

Thus, the Berlin Airlift is best described as the aircraft used to delivered needed food and supplies to the city of Berlin through the air because all other routes were blocked by the Soviet Union.

Learn more about Berlin Airlift here: brainly.com/question/1104371

#SPJ1

8 0
2 years ago
The physical structure of the earth’s rock is changed by _____.
PSYCHO15rus [73]
It could be stress or strain
4 0
3 years ago
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What is Restoring force for large waves is A. Wind, B. Capillary Action, C. Diffusion D.Friction, or E. Gravity
jek_recluse [69]
The answer would be c.diffution
7 0
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What are two types of scientific investigations?
kvv77 [185]
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Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The
IRISSAK [1]

To develop this problem we will apply the concepts related to the Electromagnetic Force. The magnetic force can be defined as the product between the free space constant, the current (of each cable) and the length of these, on the perimeter of the cross section, in this case circular. Mathematically it can be expressed as,

F= \frac{\mu_0}{2\pi} \frac{I^2L}{d}

Here,

\mu_0 = Permeability free space

I = Current

L = Length

d= Distance between them

Our values are,

L = 0.67m

m = 0.082kg

d = 7.4*10^{-3}m

I = \text{Current through each of the wires}

Rearranging the previous equation to find the current,

\frac{mg}{L} = 2*10^{-7} (\frac{I^2}{d})

I = \sqrt{\frac{mgd}{(2*10^{-7})L}}

I = \sqrt{\frac{(0.082)(9.8)(7.4*10^{-3})}{(2*10^{-7})(0.67)}}

I = \sqrt{44377.9}

I = 210.66A

Therefore the current in the rods is 210.6A

8 0
3 years ago
Read 2 more answers
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