Air enters the compressor of a cold air-standard Brayton cycle with regeneration at 100 kPa, 300 K, with a mass flow rate of 6 k

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Air enters the compressor of a cold air-standard Brayton cycle with regeneration at 100 kPa, 300 K, with a mass flow rate of 6 k

g/s. The compressor pressure ratio is 10, and the turbine inlet temperature is 1400 K. The turbine and compressor each have isentropic efficiencies of 80% and the regenerator effectiveness is 80%. For k 5 1.4, calculate (a) the thermal efficiency of the cycle. (b) the back work ratio. (c) the net power developed, in kW. (d) the rate of entropy production in the regenerator, in kW/K

Engineering

1 answer:

SVETLANKA909090 [29] · Answer 1 · 2022-10-20T04:36:19+03:00

(a) The thermal efficiency of the cycle.

The thermal efficiency of the cycle is given by
NThermal= net work/ heat supplied
NThermal= WNet/QH
=2026.08/4547.82= 44.55%

(b) The backwork ratio:
compressor work/ turbine work
=1760.76/3786.84= 0.465

(c) The net power developed:
WNet= WT-WC
WNet= 3786.84- 1760.76= 2026.08 kW