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3 years ago

When using fall arrest, free fall must be kept at or below how many feet

1 answer:

5 0

6 feet
Explanation: A few extra feet of free fall can significantly increase the arresting force on the employee, possibly to the point of causing injury. Because of this, the free fall distance should be kept at a minimum, and, as required by the standard, in no case greater than 6 feet (1.8 m).

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Nonshielded cable with a 1.5-inch diameter should have a minimum bending radius of

Flura [38]

Answer:

c is the answer because we have to double the number

6 0

2 years ago

The Air Force One (Boeing 747-200) has a long-range mission takeoff gross load 833,000 pounds (Ibm). What is Air Force One's tak

Ahat [919]

Answer:

The mass in:

1) Grams = $377765.5\times 10^{3}grams$

2) Kilograms = $377765.5kilograms$

3)Tonnes = $377.7655tonnes$

4) Megatonnes = $0.378megatonnes$

Explanation: The given mass of the aircraft in pounds is 833,000 pounds.

Part 1)

Since we know that 1 pound equals 453.5 grams thus by ratio we have

833,000 pounds = $833000lb\times 453.5\frac{g}{lb}=377765.5\times 10^{3}grams$

Part 2)

Since we know that 1000 grams equals 1 kilogram

thus the above mass in kilograms equals $\frac{377765.5\times 10^{3}}{1000}=377765.5kg$

Part 3)

Since there are 1000 kilograms in 1 tonne

thus the given mass is converted into tonnes as

$mass_{tonnes}=\frac{377765.5kg}{1000}=377.765tonnes$

Part 4)

Since 1 Mega tonne(Mton) equals 1000 tonnes thus the given mass is converted into mega tonnes as

$mass_{M\cdot tonn}=\frac{377.7655tonnes}{1000}=0.378Megatonnes$

4 0

3 years ago

Steam at 4 MPa, 400°C enters a steady-flow, adiabatic turbine through a 20 cm-diameter-pipe with a velocity of 20 m/s. It leaves

Furkat [3]

Answer:

28,8 m/s

Explanation:

In a steady flow system we can say that m1=m2 which means that the mass flow in the entrance in the same in the outlet. m is flow (kg/s)

we know that $m=\frac{1}{v} A*V$ where V (m/s) is velocity, A (m^2) ia area and v is specific volume (m^3/kg)

Since m1=m2 we can say

$\frac{1}{v_{1} } A_{1} *V_{1}=\frac{1}{v_{2}} A_{2} *V_{2}$

clearing the equation

$V_{2}= \frac{v_{2} }{v_{1}}*\frac{A_{1} }{A_{2}} *V_{1}$

we can specific volume (m^3/kg) from thermodynamic tables

for the entrance is 400°C and 4 MPa is superheated steam and v is : 0,7343 m^3/kg

In the outlet we have saturated vapor with quality (x) of 80%. In this case we get the specific saturated volume for the liquid (vf) and the specific volume for the saturated (vg) gas from the thermodynamic tables. we use the next equation to get (v) for the condition of interest, in this case 80% quality.

v= vf +x*(vg - vf)

where:

x: quality

vf = liquid-saturated-specific-volume

vg =steam-saturated-specific-volume.

for this problem

x = 0,8

vf = 0,00102991

vg = 3,24015

we get = 2,593 m^3/kg

The area is the one for a circle

$\pi *r^{2}$

r1 = 0,1 m^2 for area 1

r2=0,5 m^2 for area 2

A1 = 0,0314 m^2

A2 = 0,7853 m^2

we know that V1 is 20 m/s

replacing these values in the equation

$V_{2}= \frac{v_{2} }{v_{1}}*\frac{A_{1} }{A_{2}} *V_{1}$

we get V2 = 28,2 m/s.

3 0

3 years ago

What is 90 to the power of 46

Mnenie [13.5K]

Answer:Just multiply 90 by itself 46 times

Explanation:

do it

6 0

3 years ago

What is the minimum amplitude at time zero sine wave??

Romashka [77]

Answer:

One cycle for a sine wave is 360o or 2 radians. a) A sine wave with maximum amplitude at time t=0. The amplitude of a sine wave is maximum at the peak of the wave. Case 1: assuming that the wave is starting its cycle at t=0 then there is no phase shift for the wave at time t=0 without considering the amplitude...

5 0

3 years ago