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n200080 [17]
3 years ago
12

Employees from Company A and Company B both receive annual bonuses. What information would you need to test the claim that the d

ifference in annual bonuses is greater than $100 at the 0.05 level of significance? Write out the hypothesis and explain the testing procedure.
Mathematics
1 answer:
Natalija [7]3 years ago
5 0

Answer:

Step-by-step explanation:

This is a test of the mean difference between 2 independent groups or populations.

Let μ1 be the mean annual bonus of Company A's employees and μ2 be the mean annual bonus of Company B's employees.

The random variable is μ1 - μ2 = difference in the mean annual bonus of Company A's employees and the mean annual bonus of Company B's employees

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 ≤ μ2 H0 : μ1 - μ2 ≤ 100

The alternative hypothesis is

H1 : μ1 > μ2 H1 : μ1 - μ2 > 100

This is a right tailed test because of the inequality sign at the alternative hypothesis. We need to take samples of annual bonuses from both company's employees and find the averages. Then we would determine the test statistic as well as the p value. We would use the p value with the level of significance to make decisions

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Researchers studying starfish collected two independent random samples of 40 starfish. One sample came from an ocean area in the
krek1111 [17]

Answer:

The test statistic for the appropriate test is \frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}.

Step-by-step explanation:

The experiment conducted here is to determine whether there is a difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. north and south.

The hypothesis to test this can be defined as follows:

<em>H₀</em>: There is no difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. <em>p</em>₁ = <em>p</em>₂.

<em>Hₐ</em>: There is a difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. <em>p</em>₁ ≠ <em>p</em>₂.

The two-proportion <em>z</em>-test would be used to perform the test.

A sample of <em>n</em> = 40 starfishes are selected from both the ocean areas.

It provided that of the 40 starfish from the north, 6 were found to be over 8 inches in length and of  the 40 starfish from the south, 11 were found to be over 8 inches in length.

Compute the sample proportion of starfish from north that were over 8 inches in length as follows:

\hat p_{n}=\frac{6}{40}=0.15

Compute the sample proportion of starfish from south that were over 8 inches in length as follows:

\hat p_{s}=\frac{11}{40}=0.275

The test statistic is:

z=\frac{\hat p_{n}-\hat p_{s}}{\sqrt{P(1-P)[\frac{1}{n_{n}}+\frac{1}{n_{s}}]}}

Compute the combined proportion <em>P</em> as follows:

P=\frac{X_{n}+X_{s}}{n_{n}+n_{s}}=\frac{6+11}{40+40}=0.2125

Compute the test statistic value as follows:

z=\frac{\hat p_{n}-\hat p_{s}}{\sqrt{P(1-P)[\frac{1}{n_{n}}+\frac{1}{n_{s}}]}}

  =\frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}

Thus, the test statistic for the appropriate test is \frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}.

8 0
3 years ago
Which of the following can be used to prove that the triangle EFG is a right triangle.
Leviafan [203]
If you use a ruler and if it's more than 120° its not a right triangle it has to be 120°
8 0
3 years ago
If a 14-karat ring weighs 0.5 ounce,How many ounces of pure gold does it contain?
lianna [129]

I think it would contain 0.2915 ounces of pure gold in it. sorry if my answer isnt correct

5 0
3 years ago
Please answer the following questions​
shutvik [7]

Answer:

a) 8.8 square centimetres

b) 31.8 square centimetres

c) (3a + 12) square centimetres

d) Area = (2b + 2c + 4) square centimetres

Step-by-step explanation:

a) We have to split the diagram into three separate rectangles as shown below.

The area of A:

Area = 5.3 * 1 = 5.3 square centimetres

The area of B:

Area = 3.3 * 1 = 3.3 square centimetres

The area of C:

Area = 2 * 1 = 2 square centimetres

The area of the shape is the sum of the areas of the three shapes:

Area = 5.3 + 3.3 + 2 = 8.8 square centimetres

b) We have to split the diagram into two separate rectangles as shown below.

Note:(The diagram has conflicting values for 2.6 and 2.1 but I went with 2.6 as it seems more feasible in the diagram)

The area of A:

Area = 3 * 2.6 = 7.8 square centimetres

The area of B:

Area = 6 * 4 = 24 square centimetres

The area of the shape is the sum of the areas of the two shapes:

Area = 7.8 + 24 = 31.8 square centimetres

c) The shape is a rectangle and so its area is:

Area = 3 * (a + 4) = (3a + 12) square centimetres

d) The shape is a trapezium and so its area is:

Area = 0.5(A + B)H

where A =  c cm

B = b + 2 cm

H = 4 cm

The area of the shape is therefore:

Area = 0.5 * (c + b + 2) * 4

Area = 2 * (b + c + 2)

Area = (2b + 2c + 4) square centimetres

3 0
2 years ago
The Torrence family has a rectangular, in-ground pool in their yard. It holds 1700 ft of water. If it is 17 ft wide and 4 ft dee
xeze [42]

9514 1404 393

Answer:

  25 ft

Step-by-step explanation:

The volume is given by the formula ...

  V = LWD . . . . . the product of length, width, depth

Solving for L, we have ...

  L = V/(WD) = (1700 ft³)/((17 ft)(4 ft)) = 100/4 ft = 25 ft

The length of the pool is 25 ft.

4 0
2 years ago
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