Please help me All questions I want help.
1 answer:
Let n be the number of sides of a polygon.
To solve for the sum of the interior angles:
(n-2) x 180°
To solve for the measure of each interior angle of the polygon
[(n-2) x 180°] / n
To solve for the measure of each exterior angle:
360° / n
The sum of the exterior angles is always 360°
See attachment for answers.
To solve for the sum of the interior angles:
(n-2) x 180°
To solve for the measure of each interior angle of the polygon
[(n-2) x 180°] / n
To solve for the measure of each exterior angle:
360° / n
The sum of the exterior angles is always 360°
See attachment for answers.
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