Answer:
<h2>A. x ≤2 or x>6</h2>
Step-by-step explanation:
2x+6 ≤ 10 or 2x + 8 > 20
⇔ 2x ≤ 4 or 2x > 12
⇔ x ≤ 2 or x > 6
Answer:
3/4
Step-by-step explanation:
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1) function f(x)
x - 5
f(x) = ----------------
3x^2 - 17x - 28
2) factor the denominator:
3x^2 - 17x - 28 = (3x + 4)(x - 7)
x - 5
=> f(x) = -----------------------
(3x + 4) (x - 7)
3) Find the limits when x → - 4/3 and when x → 7
Lim of f(x) when x → - 4/3 = +/- ∞
=> vertical assymptote x = - 4/3
Lim of f(x) when x → 7 = +/- ∞
=> vertical assymptote x = 7
Answer: there are assympotes at x = 7 and x = - 4/3
Answer:
The answer is 60
Step-by-step explanation:
Just trust me :)
