Triangle ABC is equilateral, because AB=BC=AC=a. Then
m∠A=m∠B=m∠C=60°.
Let point D lie on the ray BC to the right from points B and C and let CD=x. Then BD=a+x, AB=a.
Consider triangle ACD. In this triangle, m∠ACD=180°-m∠ACB=180°-60°=120°.
By the cosine theorem,
Since then
and
Therefore, you get double inequality
or
Answer:
$12.00
Step-by-step explanation:
16-12=4
Answer:
351/1000
Step-by-step explanation: