Constant acceleration of plane = 3m/s²
a) Speed of the plane after 4s
Acceleration = speed/time
3m/s² = speed/4s
S = 12m/s
The speed of the plane after 4s is 12m/s.
b) Flight point will be termed as the point the plane got initial speed, u, 20m/s
Find speed after 8s, v
a = 3m/s²
from,
a = <u>v</u><u> </u><u>-</u><u> </u><u>u</u>
t
3 = <u>v</u><u> </u><u>-</u><u> </u><u>2</u><u>0</u>
8
24 = v - 20
v = 44m/s
After 8s the plane would've 44m/s speed.
It would be accelerating at -9.8 m/s^2 so it’s velocity would be equal to -9.8•1.1 so the answer is 10.78m/s
Answer:
1315789.47368 lines/m
Explanation:
m = Order = 1
= 1 For maximum condition
= Wavelength = 760 nm maximum
From Rayleigh criteria we have the expression for the gap

The number of lines is the reciprocal of the slit distance

The number of lines is 1315789.47368 per meter
Answer:
Linear momentum is mass multiplied by velocity, so it follows that angular momentum is the moment of inertia, measured in kilogram meters squared, multiplied by angular velocity, measured in radians per second. Radians are just an alternative to degrees.