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Sergeu [11.5K]
3 years ago
8

Fermentation is a key component in the process of fuel production known as?

Chemistry
1 answer:
kumpel [21]3 years ago
7 0
<span>Fermentation is a key component in the process of fuel production known as <u>bioconversion</u>.
Bioconversion is </span><span>the conversion of organic materials into an energy source by processes (as fermentation) involving living organisms.</span>
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Formula for Manganese Bromide Tetrahydrate
Lelu [443]

Answer:

I believe the molecular formula is MnBr2·4H2O or Br2H8MnO4

Explanation:

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3 years ago
2.50g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 12
Art [367]

Answer:

                      Molecular Formula  =  C₁₀H₈

Explanation:

Step 1: <u>Calculating Moles for each Element:</u>

C  =  Mass of CO₂ × (1 mol of CO₂÷ M.Mass of CO₂) × (1 mol of C ÷ 1 mol of CO₂)

C  =  8.60 g × (1 mol of CO₂÷ 44.011 g.mol⁻¹) × (1 mol of C ÷ 1 mol of CO₂)

C =  0.1954 mol

H  =  Mass of H₂O × (1 mol of H₂O ÷ M.Mass of H₂O) × (2 mol of H ÷ 1 mol of H₂O)

H  = 1.41 g × (1 mol of H₂O ÷ 18.106 g.mol⁻¹) × (2 mol of H ÷ 1 mol of H₂O)

H =  0.1557 mol

Step 2: <u>Calculate the Smallest whole number ratio as,</u>

                                 C                                                        H

                              0.1954                                               0.1557

                      0.1954/0.1557                                  0.1557/0.1557

                               1.25                                                       1

Multiply ratio by 4,

                                 5                                                         4

Result:

          Empirical Formula of Propane is C₅H₄

Step 3: <u>Calculate Molecular Formula:</u>

Molecular formula is calculated by using following formula,

                    Molecular Formula  =  n × Empirical Formula  ---- (1)

Also, n is given as,

                     n  =  Molecular Weight / Empirical Formula Weight

Molecular Weight  =  128.0 g.mol⁻¹

Empirical Formula Weight  =  5 (C) + 4 (H) =  64 g.mol⁻¹

So,

                     n  =  128.0 g.mol⁻¹ ÷ 64 g.mol⁻¹

                     n  =  2

Putting Empirical Formula and value of "n" in equation 1,

                    Molecular Formula  = 2 × C₅H₄

                    Molecular Formula  =  C₁₀H₈

4 0
3 years ago
Air is an example of a mixture because the elements and compounds that make up air retain their individual properties. T or F
netineya [11]

Answer:

True

Explanation:

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Calculate the percentage by mass of nitrogen in ptcl2(nh3)2.
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Molar Mass: 300.0510 g/mol
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