The primary reason some parts of Earth are hotter than other parties because the hotter parts of Earth

Si en un planeta la presión atmosférica es mayor que 5,1 atm terrestres, los habitantes podrían nadar en ríos de dióxido de carb

Sphinxa [80]

Answer:

Los habitantes del planeta con una atmósfera superior a 5,1 atm de la Tierra, no estarían nadando en ríos de dióxido de carbono líquido

Explanation:

De las tablas de datos termodinámicos, la presión a la que el vapor de dióxido de carbono está en equilibrio con su estado líquido a una temperatura ambiente de 25 ° C es 6,401 kPa, lo que equivale a 63,17296 atm.

Por lo tanto, a una presión de 5.1 de la atmósfera terrestre, el dióxido de carbono es completamente gaseoso y los habitantes del planeta con una presión atmosférica de 5.1 atm de la Tierra todavía observarían solo hidrógeno gaseoso y no estarían nadando en ríos de dióxido de carbono líquido.

5 0

2 years ago

CAN SOMEONE HELP ME PLEASE . i have the definitions i just need help with examples

Alla [95]

Collision Coverage Example:
You're driving down the street and rear end the car in front of you. Your liability insurance will pau for the damage done to the other car, and your Collision insurance (or coverage) will pay for the damage done to your own vehicle because this was an accident in which you collided with another vehicle.

Comprehensive Coverage Example:
When there's damage to your windshield; damage from natural disasters and bad weather conditions, like wind storms, hurricanes, floods, earthquakes, hail, etc,.

Hope I helped!

6 0

3 years ago

What would the Net Ionic Equation be for the following:

marin [14]

The net equations are obtained from the double displacement of the cations and anions, then balance.

NH3(aq) + HC2H3O2 (aq) = NH4+(aq) + C2H3O2-(aq<span>)
</span><span>H+(aq) + C2H3O2-(aq) + NH3(aq) -> NH4+(aq) + C2H3O2-(aq)</span><span>

</span><span>2NaOH(aq) + H2SO4 (aq) = Na2SO4 (s)+ 2H2O (aq)
</span>H2S (aq) + Ba(OH)2 (aq) = BaS (s)+ 2H2O (aq)

3 0

2 years ago

The theoretical yield of 1,2-epoxycyclohexane is _______________ grams, when starting with 3.0 grams of trans-2-bromocyclohexano

Amanda [17]

Answer:

1.64g

Explanation:

The reaction scheme is given as;

2-bromocyclohexanol --> 1,2-epoxycyclohexane + HBr

From the reaction above,

1 mol of 2-bromocyclohexanol produces 1 mol of 1,2-epoxycyclohexane

3.0 grams of trans-2-bromocyclohexanol.

Molar mass = 179.05 g/mol

Number of moles = mass / molar mass = 3 / 179.05 = 0.016755 mol

This means 0.016755 mol of 1,2-epoxycyclohexane would be produced.

Molar mass = 98.143 g/mol

Theoretical yield = Number of moles * Molar mass

Theoretical yield = 0.016755 * 98.143 ≈ 1.64g

7 0

3 years ago

6. How many moles of water would require 92.048 kJ of heat to raise its temperature from 34.0 °C to 100.0 °C? (3 marks)

scoray [572]

Taking into account the definition of calorimetry, 0.0185 moles of water are required.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

<h3>Mass of water required</h3>

In this case, you know:

Heat= 92.048 kJ
Mass of water = ?
Initial temperature of water= 34 ºC
Final temperature of water= 100 ºC
Specific heat of water = 4.186 $\frac{J}{gC}$

Replacing in the expression to calculate heat exchanges:

92.048 kJ = 4.186 $\frac{J}{gC}$ × m× (100 °C -34 °C)

92.048 kJ = 4.186 $\frac{J}{gC}$ × m× 66 °C

m= 92.048 kJ ÷ (4.186 $\frac{J}{gC}$ × 66 °C)

<u><em>m= 0.333 grams</em></u>

<h3>Moles of water required</h3>

Being the molar mass of water 18 $\frac{g}{mole}$ , that is, the amount of mass that a substance contains in one mole, the moles of water required can be calculated as: