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pashok25 [27]
3 years ago
10

Maria is 7 years older than her brother Robert and in 2 years her age will be four times what Robert’s age was three years ago.

Find their present ages.
Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
8 0
Robert is 7 years old and Maria is 14.
Digiron [165]3 years ago
8 0

Answer:

MARIA=14

ROBERT=7

Step-by-step explanation:

<u>Now</u>

MARIA=X+7

ROBERT=X

<u>In 2 years</u>

MARIA=X+7+2=X+9

ROBERT=X+2

<u>3 years a</u>go

MARIA=X+7-3=X+4

ROBERT=X-3

<u>EQUATION</u>

X+9=4(X-3)

X+9=4x-12

X-X+9=4x-x-12

9=3x-12

3x=21

X=7

ROBERT=7

MARIA=7+7=14

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A ). 12

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At the movie theater child admission is 6000 and $.30 an adult mission is $9.60 on Wednesday 172 tickets were sold for a total s
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Answer:

The number of child tickets sold was 75 and the number of adult tickets sold was 97

Step-by-step explanation:

<u><em>The correct question is</em></u>

At the movie theater child admission is $6.30 an adult admission is $9.60 on Wednesday 172 tickets were sold for a total sales of $1403.70 How many child tickets and adult tickets were sold that day?

Let

x ----> number of child tickets sold

y ----> number of adult tickets sold

we know that

x+y=172 ----> equation A

6.30x+9.60y=1,403.70 -----> equation B

Solve the system by graphing

Remember that the solution of the system is the intersection point both lines

Using a graphing tool

The intersection point is (75,97)

see the attached figure

therefore

The number of child tickets sold was 75 and the number of adult tickets sold was 97

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Ava has been asked to create the advertising art for the school skating party. She is using paper that is 15.5 inches wide. The
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A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

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Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

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Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

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