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3 years ago

6

The straight lines passing through these pairs of points (2, 5) and (4, 7) ,(−4, 2) and (1, 7) are,

2 answers:

Serhud [2]3 years ago

7 0

Answer:

B. Perpendicular

Step-by-step explanation:

This is the short version.

Hope this helps!

Taya2010 [7]3 years ago

5 0

Answer:

The line passes (2, 5) and (4, 7) has slope:

S = (7 - 5)/(4 - 2) = 2/2 = 1

The line passes (1, 7) and (-4, 2) has slope:

S = (2 - 7)/(-4 - 4) = 5/-5 = -1

The multiplication of two slope is 1 x (-1) = -1

=> Two lines are perpendicular

Hope this helps!

:)

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Solve the system by elimination.(show your work)

PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

6 0

3 years ago

Read 2 more answers

4. Stella says the equation x^2−8x+y^2+2y=5 has a center of (4,−1) and a radius of 5. Is she correct? Why or why not?

Ostrovityanka [42]

<h2>Stella is correct about center and wrong about radius </h2>

Step-by-step explanation:

Equation of circle with (h,k) as center and radius r is given by,

(x-h)²+(y-k)² = r²

Here equation is

x²−8x+y²+2y=5

Changing in to (x-h)²+(y-k)² = r² form

x²−8x + 16 - 16 +y²+2y+1 - 1=5

(x-4)² - 16 + (y+1)² -1 = 5

(x-4)² + (y+1)² = 22

(x-4)² + (y+1)² = 4.69²

Center is (4,-1) and radius is 4.69

Stella is correct about center and wrong about radius

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What is 0.0003124 in scientific notation?

Shalnov [3]

3.124 * 10^-4

since your decimal is coming forward you need the exponent to be negative

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MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

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so -9≤2x-3≤9

add 3 to each inequality

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divide by 2

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3 years ago

Alan averages 10 hits out of 25 shots at the target. What is the chance that he will hit his next two attempts?

Sveta_85 [38]

The answer is that he has a 40% chance 10*100=1000 1000/25=40 Making it a 40% chance

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