Answer:
23
Step-by-step explanation:
With f(4), we plug 4 into the function.
f(4) = 4² + 7
f(4) = 16 + 7
f(4) = 23
Answer:
what are the ordered pairs? then graph them and do the y axis number over the x axis number
Step-by-step explanation:
<span>the quadratic function that is created with roots -3 and 1 is:
f(x) = a(x + 3)(x - 1) = a(x^2 + 2x - 3) = a(x^2 + 2x) - 3a . . . . . . . . (1)
</span><span><span>the quadratic function that is created with</span> vertex at (-1, -8) is:
a(x + 1)^2 - 8 = a(x^2 + 2x + 1) - 8 = a(x^2 + 2x) + a - 8 . . . . . . . . (2)
From (1) and (2): a - 8 = -3a
4a = 8
a = 2
Therefore, required function is f(x) = 2(x^2 + 2x) - 3(2) = 2x^2 + 4x - 6
</span>
The required number which when decreased by 8 is divisible by 21, 27, 33, and 55 is 10403.
We need to find the smallest number which when decreased by 8 is divisible by 21, 27, 33, and 55.
<h3>What is LCM?</h3>
The least common multiple is also known as LCM (or) the lowest common multiple in math. The least common multiple of two or more numbers is the smallest number among all common multiples of the given numbers.
We find the LCM of 21, 27, 33, and 55.
3 | 21 27 33 55
3 | 7 9 11 55
3 | 7 3 11 55
7 | 7 1 11 55
5 | 1 1 11 55
11 | 1 1 11 11
| 1 1 1 1
When decreased by 8, we have to add 8 in the LCM of the numbers.
That is 10395+8=10403
Therefore, the required number when decreased by 8 is divisible by 21, 27, 33, and 55 is 10403.
To learn more about the LCM of numbers visit:
brainly.com/question/10942748.
#SPJ4
As the GCF is 3x let us write a polynomial and then multiply it by 3x.
Here is a polynomial:
If we multiply it by 3x we get
. Since we have a product (two expressions being multiplied together) this is factored. So this is the factored form of the polynomial we created with GCF of 3x.
Let’s multiply the terms in the parenthesis by 3x to get the same polynomial but written a different way:
. This is the factorable polynomial and the one we had before is the factored polynomial (also an equivalent form)
To get another equivalent form I could multiply out only the first term. This gives us
another equivalent form.
