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3 years ago

Please help find the value of x please:)

Mathematics

1 answer:

ryzh [129]3 years ago

5 0

Answer: 100

Step-by-step explanation:

An isosceles right triangle therefore has angles of 45 degrees, 45 degrees, and 90 degrees. For an isosceles right triangle with side lengths a, the hypotenuse has length $\sqrt(2)a$ .

Therefore $x=100\sqrt{2} /\sqrt{2}=100$

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Samantha Cruz has 200 coins (quarters and dimes). She has $44.00. Write a system of equations and determine how many quarters= _

marishachu [46]

Answer:

Step-by-step explanation:

how many coins: d + q = 200

value of the money .10d + .25q = 44

(ten cents for each dime and 25 cents for each quarter)

Now to solve by elimination:

1)multiply the first row by -10 so that the dimes will cancel out.

-.10d + -.10 q = 20 (don't do anything to second row)

.10d + .25q = 44

2) now add those up.

the dimes cancel out.

.15 q = 64

that does not divide evenly so there is something wrong with this problem.

4 0

3 years ago

My dad uses a reusable cup every time every time he goes to the coffee shop the coffee shop takes $0.10 off each coffee every ti

Ronch [10]

He would save 70 cents because .10 x 7 = .7
and .7 x 100 is 70

8 0

4 years ago

Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065. New equipment is being

Ilya [14]

Answer:

Yes, the new equipment appear to be effective in reducing the variation of weights.

Step-by-step explanation:

We are given that Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065.

A simple random sample of 25 quarters is obtained from those manufactured with the new equipment, and this sample has a standard deviation of 0.047.

Let $\sigma$ = standard deviation of weights of new equipment.

SO, Null Hypothesis, $H_0$ : $\sigma \geq$ 0.065 {means that the new equipment have weights with a standard deviation more than or equal to 0.065}

Alternate Hypothesis, $H_A$ : $\sigma$ < 0.065 {means that the new equipment have weights with a standard deviation less than 0.065}

The test statistics that would be used here One-sample chi-square test statistics;

T.S. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2}__n_-_1$

where, s = sample standard deviation = 0.047

n = sample of quarters = 25

So, the test statistics = $\frac{(25-1)\times 0.047^{2} }{0.065^{2} }$ ~ $\chi^{2}__2_4$

= 12.55

The value of chi-square test statistics is 12.55.

Now, at 0.05 significance level the chi-square table gives critical value of 13.85 at 24 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 12.55 < 13.85, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the new equipment have weights with a standard deviation less than 0.065.

5 0

3 years ago

If STUV is a square with SW = 2x + 13 and WU = 8x - 41, find VT. 20 points

sergejj [24]

Answer: VT equals 62

Step-by-step explanation: In the square with sides STUV, the point W is a midpoint on the diagonal of the square such that the diagonal line SU is divided into two equal halves by the lines SW and WU. Also note that a square has two diagonals whose measurements are equal, that is, line SU equals line VT.

If the point W is the midpoint of SU, then we can conclude that SW equals WU. This means;

2x + 13 = 8x - 41

Collect like terms and you now have,

13 + 41 = 8x - 2x

54 = 6x

Divide both sides of the equation by 6

9 = x

Having calculated the value of x, remember that SW plus WU equals SU. And diagonal SU equals diagonal VT.

Therefore, VT is calculated as follows;

VT = SW + WU

VT = 2x + 13 + 8x - 41

VT = 2(9) + 13 + 8(9) - 41

VT = 18 + 13 + 72 - 41

VT = 62

8 0

3 years ago

What is 1,144,646 rounded to the nearest million

marta [7]

Answer:

1,000,000

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers