Question

For each function, find f(-2), f(-0.5), and f(3). 1. f(x)=-x+4 2. f(x)= 3/8x-3

Answer 1

Answer:  The calculations are done below.

Step-by-step explanation: We are given to find the values f(-2), f(-0.5) and f(3) for each of the given functions.

The first function is

$f(x)=-x+4.$

So, we get

$f(-2)=-(-2)+4=2+4=6,\\\\f(-0.5)=-(-0.5)+4=0.5+4=4.5,\\\\f(3)=-(3)+4=-3+4=1.$

The second function is

$f(x)=\dfrac{3}{8}x-3.$

So, we get

$f(-2)=\dfrac{3}{8}(-2)-3=-\dfrac{3}{4}-3=-\dfrac{15}{4},\\\\\\f(-0.5)=\dfrac{3}{8}\times(-0.5)-3=\dfrac{3}{8}\times\left(-\dfrac{1}{2}\right)-3=-\dfrac{3}{16}-3=-\dfrac{51}{16},\\\\\f(3)=\dfrac{3}{8}\times3-3=\dfrac{9}{8}-3=-\dfrac{15}{8}$

Thus, all the values are found.

Answer 2

The values of  f(-2), f(-0.5), and f(3) can be solved by substituting the values inside the parentheses to the function to the variable x. We do as follows:

1. f(x)=-x+4

f(-2) =-x+4 = 2+4 = 6

f(-0.5) =-x+4 = 0.5 + 4 = 4.5

f(3) =-x+4 = -3+4 = 1


2. f(x)= 3/8x-3

f(-2)= 3/8x-3 = -15/4
 
f(-0.5) = 3/8x-3 = -51/16

f(3) = 3/8x-3 = -15/8

Hope these answers the question.