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Assoli18 [71]
3 years ago
11

Imagine an isolated positive point charge Q (many times larger than the charge on a single proton). There is a charged particle

A (whose charge is much smaller than charge Q) at a distance from the point charge Q. On which of the following quantities does the magnitude of the electric field created by charge Q at particle A's position depend?a) the amount of the charge on the point charge Qb) the specific location of the charged particle A (while the distance between Q and A is fixed)c) the specific location of the point charge Q (while the distance between Q and A is fixed)d) the type of the charge on the charged particle Ae) the relative orientation between Q and A (while the distance between Q and A is fixed)f) the distance between the point charge Q and the charged particle Ag) the amount of the charge on the charged particle A
Physics
1 answer:
Delvig [45]3 years ago
4 0

Answer:

b) the specific location of the charged particle A

f) the distance between the point charge Q and the charged particle A

Explanation:

For this exercise we write the electric field

      E = k Q / r²

where r is the distance between charge Q and test charge A

Let's examine the different claims

a) do not depend. The charge of the individual is independent of the elective field

b) depends. The position of the particle is different if it has the same distance

c) do not depend. The particle Q must be considered the origin of the coordinate system

d) does not depend. The charge of a particle is independent of the field where it is

e) does not depend. The position of the particle is fixed

f) depends. The field is different for each distance

g) does not depend. The amount of electric charge is independent of the field

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Name a suitable plece of equipment that could be used to measure the length of the pool.​
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Answer:

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3 years ago
Two particles, one with charge −7.97×10−6 C and the other with charge 6.91×10−6 C, are 0.0359 m apart. What is the magnitude of
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Answer:

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Explanation:

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F= Kq1q2/r^2

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7 0
2 years ago
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7 0
3 years ago
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A child uses a rubber band to launch a bottle cap at an angle of 37.0° above the horizontal. The cap travels a horizontal distan
zavuch27 [327]

Answer:

Initial velocity will be 1.356 m/sec      

Explanation:

Let the initial speed = u

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Horizontal component of initial velocity u_x=ucos\Theta =ucos37^{\circ}=0.7986u

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We know that distance = speed × time

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2 years ago
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