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3 years ago

if y = 2x + 7 were changed to y = 1/2 x + 7 , how would the graph of the new function compare with the original ?

2 answers:

8 0

Y = 2x + 7.....the slope is 2 and the y int is 7
y = 1/2x + 7...the slope is 1/2 and the y int is 7

In comparison, the only difference is the slope. And if the original equation has a slope of 2, and it is changed to a slope of 1/2, then it will have a " less steep " slope. In other words, the slope will not be as steep....but the y intercepts will be the same.

dmitriy555 [2]3 years ago

5 0

Answer:

It would be less steep

Step-by-step explanation:

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3 years ago

The average of 6 numbers is 7. When a 7th number is addedThe average of all numbers is 0. What is the seventh number?

Katena32 [7]

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3 years ago

Solve the absolute value equation |x| − 2 = 5 to find the distance Mary can walk forward, x, in 5 seconds.

Alisiya [41]

Answer:

x = 7 m and x = −7 m

Step-by-step explanation:

Its a modulus problem

concept

|x| = x when x>=0

|x| = -x when x < 0

____________________________________

Now given

|x| − 2 = 5

adding 2 both sides

|x| − 2 + 2 = 5 + 2

|x| = 7

now

x = 7 when x >= 0

x = -7 when x<0

Thus, correct answer is x = 7 m and x = −7 m

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4 years ago

Daisies phone calls for an ask her to meet at the park in exactly 40 minutes which method should daisy use to most accurately de

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3 years ago

Read 2 more answers

Neil is a drummer who purchases his drumsticks online. When practicing with the newest pair, he notices they feel heavier than u

Fynjy0 [20]

Answer:

The probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

Step-by-step explanation:

Given:

Weight of a given sample (x) = 2.33 oz

Mean weight (μ) = 1.75 oz

Standard deviation (σ) = 0.22 oz

The distribution is normal distribution.

So, first, we will find the z-score of the distribution using the formula:

$z=\frac{x-\mu}{\sigma}$

Plug in the values and solve for 'z'. This gives,

$z=\frac{2.33-1.75}{0.22}=2.64$

So, the z-score of the distribution is 2.64.

Now, we need the probability $P(x\geq 2.33 )=P(z\geq 2.64)$ .

From the normal distribution table for z-score equal to 2.64, the value of the probability is 0.9959. This is the area to the left of the curve or less than z-score value.

But, we need area more than the z-score value. So, the area is:

$P(z\geq 2.64)=1-0.9959=0.0041=0.41\%$

Therefore, the probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

5 0

3 years ago