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2 years ago

I need help with this.

Mathematics

1 answer:

nekit [7.7K]2 years ago

3 0

Do this base time hight

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Solve the inequality lxl <5.

Lorico [155]

Answer:

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3 years ago

Patrick earns $40 per hour. He earned an extra $1000 for working on a special project. His pay check for the month was 7420. How

Likurg_2 [28]

Patrick worked 160.5 hours because you have to subtract 1000 from 7420 then divide that by 40 for your answer. Also, Patrick has a sweet job.

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2 years ago

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8,128 in expanded form

Brilliant_brown [7]

Answer:

8000,100,20,8

Step-by-step explanation:

explantion

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2 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

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2 years ago

Charles can type 675 words in 9 minutes. How many words can Charles type in 13 minutes?

tangare [24]

Charles can type 975 in 13 mins

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