We need to solve x+2y=11 for x
Let's start by adding -2y to both sides
x+2y -2y = 11-2y
x= -2y+11
Now substitute -2y+11 for x in x-2y =-1
x-2y=-1
-2y+11-2y=-1
-4y+11=-1
Add -11 to both sides
-4y+11-11=-1-11
-4y=-12
Divide both sides by -4
-4y/-4 = -12/-4
y= 3
Substitute 3 for y in x=-2y+11
x= -2y+11
x = (-2)(3)+11
x=-6+11
x=5
The answer is x=5 and y=3
(5,3)
I hope that's help:)
F(x) = 6(9)^x
f(1/2) = 6(9)^(1/2)
f(1/2) = 6(9)^(0.5)
f(1/2) = 6*(9^0.5) 9^0.5 = √9 = +3 or -3.
f(1/2) = 6*3 = 18 or 6*-3 = -18
f(1/2) = 18 or -18
Hope this helps.
The answer would be D yeahhhhhh
Answer:
∠ K = 35° and ∠ L = 105°
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
let ∠ K = x then ∠ L = 3x
Sum the angles and equate to 180
3x + x + 40 = 180, that is
4x + 40 = 180 ( subtract 40 from both sides )
4x = 140 ( divide both sides by 4 )
x = 35
Thus
∠ K = 35° and ∠ K = 3x = 3 × 35 = 105°
Given:
To find:
The quadrant of the terminal side of 
and find the value of 
.
Solution:
We know that,
In Quadrant I, all trigonometric ratios are positive.
In Quadrant II: Only sin and cosec are positive.
In Quadrant III: Only tan and cot are positive.
In Quadrant IV: Only cos and sec are positive.
It is given that,
Here cos is positive and sine is negative. So, 
must be lies in Quadrant IV.
We know that,
It is only negative because lies in Quadrant IV. So,
After substituting , we get
Therefore, the correct option is B.
