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dalvyx [7]
2 years ago
15

Will Mark Brainliest

Mathematics
1 answer:
Mademuasel [1]2 years ago
4 0

we are given with the data of a parabola with vertex at (2, 2) and directrix at y  = 2.5. the formua should be ax^2 + b x + c = y because of the directrix. 

(x-h)^2 = 4a (y-k)

(x-2)^2 =4a (y-2) 

a is the equidistant distance from focus to vertex and from vertex to directrix that is equal to -0.5

then the  answer is 

(x-2)^2 =-0.5*4 (y-2) 

x2 - 4x + 4 = -2y +4

x2-4x+2y = 0

answer is C

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JulijaS [17]

Answer:

The scale factor is 2/3.

Step-by-step explanation:

Given data,

The given image is (6,9)

The image after dilation is (4,6)

The scale factor is calculated by dividing the resultant image by the initial image.

For example, if the initial dimensions are (x1, y1) and the final dimensions are (x2,y2). The scale factor is calculated using x2/x1 = y2/y1 = Scale Factor  

In our scenario,

x1  = 6

x2 = 4

y1  = 9

y2 = 6

Scale Factor = x2/x1

=> 4/6

=> 2/3

Similarly for y axis,

Scale Factor = y2/y1

=> 6/9

=> 2/3

Therefore, the scale factor is 2/3.

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Factor completely. 5x^2+44x-9
Leni [432]

Answer:

(x + 9)(5x - 1)

Step-by-step explanation:

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The factors are + 45 and - 1

Use these factors to split the x- term

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The graph of a rational function f is shown below.
Mashutka [201]

We have y+2 = 0 and x - 2 = 0. The provided function has an x and y-intercept of -2 and +2, respectively. There is no vertical asymptote. Two is the horizontal asymptote.

<h3>What is a graph?</h3>

A diagram depicting the relationship between two or more variables, each measured along with one of a pair of axes at right angles.

The y-intercept of a function is determined by the intersection of its graph with the y-axis. The value of y on the y-axis at which the considered function crosses it is called the y-intercept.

Assume the following equation: y = f (x)

We have x   =0- 2 and y+2 = 0,The x and y intercept of the given function is -2 and +2.

The vertical asymptote is none. The horizontal asymptote is 2.

Hence,we have y+2 = 0 and x - 2 = 0. The provided function has an x and y-intercept of -2 and +2, respectively. There is no vertical asymptote. Two is the horizontal asymptote.

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brainly.com/question/14375099

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