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rosijanka [135]
3 years ago
15

Whats the Independent and Dependent variable of this equation? y = 2x + 5

Mathematics
1 answer:
Slav-nsk [51]3 years ago
8 0
The dependent variable is the one on the left side of the equal sign (y).
The independent variable is the one on the right side of the equal sign (x).
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1. What is the perimeter of the figure below. Simplify.<br> 4x^3-5x 2x^3+6x 6x^3+x
____ [38]

Answer:

12x^3+2x

Step-by-step explanation:

The perimeter of a polygon is equal to the sum of its sides.

The sides in the triangle shown have lengths 2x^3+6x, 4x^3-5x, and 6x^3+x in no specific order.

Since its perimeter is given by the sum of its sides, the perimeter is equal to:

2x^3+6x+4x^3-5x+6x^3+x

Combine like terms:

\boxed{12x^3+2x}

6 0
3 years ago
What is the product?
cestrela7 [59]

Answer:

-8265

Step-by-step explanation:

8 0
2 years ago
Simplify <br> ( 5w + 13 ) + ( 2w + 1)
Vadim26 [7]

Answer:

10w^2 + 24w + 13

Step-by-step explanation:

use Foil method

6 0
3 years ago
Read 2 more answers
Find the area of the figure. Round to the nearest hundredth when necessary.
Delvig [45]

Answer:

215.20 ft^2

Step-by-step explanation:

The figure has 2 semi-circles.

First we find the area of each circle using the formula \pi r^{2} because that is the area formula for a circle.

The semi-circle to the left gives the diameter which is 22 feet. The radius would be half the diameter thus r=11 for semi-circle one.

Then we are to find the diameter of the second semi-circle. Given the entire length to be 30 feet, 30-22 leaves us with 8 feet as its diameter thus r=4.

Left: r=11

Right: r=4

Then, plugging both into the formula for area of a circle, we get

Left: 380.1327

Right: 50.26548

We must divide each by two because we are only looking for semi-circle which is exactly half the area of a full circle.

Then,

Left: 190.066

Right: 25.1327

190.066+ 25.1327= 215.199 = 215.2ft^2

8 0
3 years ago
Factor the expression using the GCF<br> 42+14
melomori [17]
14 is the answer sorry if I get it wrong :/
6 0
3 years ago
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