Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
X^2+12x=0
(ax^2+bx)=0
(b/2)^2=(12/2)^2=(6)^2=36
x^2+12x+36=(x+6)^2
So Congruent. Two figures are congruent if they have the same shape and size. Two angles are congruent if they have the same measure. Two figures are similar if they have the same shape but not necessarily the same size.
I hope that help u:)
Since the values are the same on both sides the matrix value is a=1
Answer:
y = 189.8
Step-by-step explanation:
Apply trigonometric function to find y.
Reference angle (θ) = 50°
Adjacent side = 122
Hypotenuse = y
Apply CAH, since the Hypotenuse and the Adjacent are involved.
Thus:
Cos θ = Adj/Hypo
Plug in the values
Cos 50° = 122/y
y*Cos 50° = 122
y = 122/cos 50°
y = 189.8 (beater tenth)
