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ipn [44]
3 years ago
14

The alpha decay of a radioactive nuclide (X) emits a He-4 nucleus and produces an isotope of Superscript 235 subscript 92 upper

U.. What is X? Superscript 235 subscript 91 upper P a. Superscript 235 subscript 93 upper N p. Superscript 236 subscript 92 upper U. Superscript 239 subscript 94 upper P u.
Chemistry
1 answer:
kupik [55]3 years ago
7 0

Answer:

Superscript 239 subscript 94 upper P u

(plutonium-239)

Explanation:

In alpha decay, the element subtracts 4 from its mass number and subtracts 2 from its atomic number.

So if we end with Uranium-235, which has an atomic number of 92:

235+4 = 239

92+2 = 94

Element 94 is Pu, plutonium, and its mass could very well be 239 if it's an isotope. So the answer is Superscript 239 subscript 94 upper P u.

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How does an adaptation begin?
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Read 2 more answers
Which would be most suitable for measuring 2.7 mL of ethanol for addition to a reaction with acidified dichromate?
pochemuha

Answer : The correct option is, (C) 10-mL volumeric pipet.

Explanation :

Graduated cylinder : It is a measuring cylinder that is used to measure the volume of a liquid. It has a narrow cylindrical shape. The marked line drawn on the graduated cylinder shows the amount of liquid that has been measured.

Pipet : It is a type of laboratory equipment that is used to measure the volume of a liquid. It is small glass tube and the marked line drawn on the pipet. It is used to accurately measure and transfer of volume of liquid from one container to another.

Volumetric flask : It is a type of laboratory tool that is also used for measuring the volume of liquid. It is used to make up a solution to a known volume. It measure volumes much more precisely than beakers.

Beaker : It is a type of laboratory equipment that has cylindrical shape and it is used for the mixing, stirring, and heating of chemicals.

As per question, we conclude that the pipet is most precise than other devices because in pipet the marking lines are more accurate. Thus, it can be used to measure volume to precision.

Hence, the correct option is, (C) 10-mL volumeric pipet.

8 0
2 years ago
I need this answer quick please show work
Ainat [17]

Answer:

The answer to your question is 25.2 g of acetic acid.

Explanation:

Data

[Acetic acid] = 0.839 M

Volume = 0.5 L

Molecular weight = 60.05 g/mol

Process

1.- Calculate the number of moles of acetic acid

    Molarity = moles / volume

-Solve for moles

    moles = Molarity x volume

-Substitution

    moles = (0.839)(0.5)

-Result

    moles = 0.4195

2.- Calculate the mass of acetic acid using proportions and cross multiplications

                   60.05 g ----------------------- 1 mol

                        x        ----------------------- 0.4195 moles

                        x = (0.4195 x 60.05) / 1

                        x = 25.19 g

3.- Conclusion

25.2 g are needed to prepare 0.500 L of Acetic acid 0.839M

               

4 0
3 years ago
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