Which component is required for the activation of some enzymes?

2 answers:

5 0

The best answer is letter A.
The main factors that change the speed of enzymatic reactions are temperature, pH and substrate concentration (quantity). <span>There are enzymes that need other associated molecules to work. These molecules are called enzyme co-factors. They can be organic ions like mineral salts.</span>

Alexus [3.1K]2 years ago

5 0

The correct answer is option A.

Presence of a co-factor is required for the activation of some enzymes. Co-factors are generally metal ions or small molecules (non-protein).Co-factors helps enzymes bind substrate tightly. For example, NAD⁺/NADH is a co-factor which is required for the activation of the enzyme dehydrogenase. NAD⁺ is the oxidized form and NADH is the reduced form.

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Earthquakes are common at ocean-continent convergence zones but not ocean-ocean convergence zones. TRUE FALSE Check it

Maru [420]

Answer:

FALSE

Explanation:

The earthquakes are common in both types of convergences is oceanic and continental and ocean to oceanic convergence. As the process of subduction takes places at the oceanic - oceanic boundary and resultant plate slide down other plate leading to recycling of the crust, volcanic eruptions and this leads to the formation of a volcanic arc, trenches, and faults.

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2 years ago

(40 Points) Complete, balance, compute the amounts of the products assuming 100% yield. 10g Na + 10g Oxygen.

Lilit [14]

13.5g

Explanation:

Given parameters:

Mass of Na = 10g

Mass of O₂ = 10g

Unknown:

Mass of products formed = ?

Balanced equation = ?

Solution:

The balanced chemical equation is shown below:

4Na + O₂ ⇒ 2Na₂O

In any reaction, the specie in short supply determines the extent of the reaction.

This reaction is not an exclusion. We need to first determine the specie in short supply and use it to estimate the amount of product since we have a 100% yield which signifies that all was used up.

let us convert to moles;

Number of moles of Na = $\frac{mass }{molar mass} = \frac{10}{23}$ = 0.435mole