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Burka [1]
3 years ago
7

You have an unknownthat contains only one cation (it is oneof the twelve from this experiment).Your solution is colorless and od

orless. Treatment with HCl producesawhite precipitate.Treatment with H2SO4 produces a white precipitate. Treatment with NaOHproducesa white precipitate that dissolves when excess NaOHis added.What isthe identity of your cation
Chemistry
1 answer:
algol [13]3 years ago
5 0

Answer:

Your cation is Pb2+

Explanation:

This is the explanation by chemical reactions

HCl (l) ----> H+(aq)  +  Cl-(aq)

Pb2+(aq)  +  2Cl-(aq)  --->  PbCl2 (s) ↓

H2SO4 (l) ----> 2H+ (aq)  +  SO4-2(aq)

Pb2+(aq)  +  SO4-2(aq) ---> PbSO4 (s) ↓

NaOH (l) ---> Na+(aq) + OH-(aq)

Pb2+(aq)  +  2OH-(aq) ---> Pb(OH)2 (s) ↓

If the reaction takes place in a strong alkaline medium, lead hydroxide dissolves in excess of base

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