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Burka [1]
3 years ago
7

You have an unknownthat contains only one cation (it is oneof the twelve from this experiment).Your solution is colorless and od

orless. Treatment with HCl producesawhite precipitate.Treatment with H2SO4 produces a white precipitate. Treatment with NaOHproducesa white precipitate that dissolves when excess NaOHis added.What isthe identity of your cation
Chemistry
1 answer:
algol [13]3 years ago
5 0

Answer:

Your cation is Pb2+

Explanation:

This is the explanation by chemical reactions

HCl (l) ----> H+(aq)  +  Cl-(aq)

Pb2+(aq)  +  2Cl-(aq)  --->  PbCl2 (s) ↓

H2SO4 (l) ----> 2H+ (aq)  +  SO4-2(aq)

Pb2+(aq)  +  SO4-2(aq) ---> PbSO4 (s) ↓

NaOH (l) ---> Na+(aq) + OH-(aq)

Pb2+(aq)  +  2OH-(aq) ---> Pb(OH)2 (s) ↓

If the reaction takes place in a strong alkaline medium, lead hydroxide dissolves in excess of base

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ELEN [110]

Answer:

I answered first, give me brainliest

Explanation:

8 0
2 years ago
The atomic number of an element is determined by the number of electrons in the nucleus of the atom.
iren [92.7K]
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The number of electrons/protons is the one that determines the atomic number of an element.
7 0
3 years ago
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What is the attraction between molecules within a substance called? adhesion capillary action cohesion polarity.
cestrela7 [59]

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cohesion

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5 0
2 years ago
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if the spin of one electron in an orbital is clockwise , what is the spin of the other electron in that orbital
nata0808 [166]

Here we have to get the spin of the other electron present in a orbital which already have an electron which has clockwise spin.

The electron will have anti-clockwise notation.

We know from the Pauli exclusion principle, no two electrons in an atom can have all the four quantum numbers i.e. principal quantum number (n), azimuthal quantum number (l), magnetic quantum number (m) and spin quantum number (s) same. The importance of the principle also restrict the possible number of electrons may be present in a particular orbital.

Let assume for an 1s orbital the possible values of four quantum numbers are n = 1, l = 0, m = 0 and s = \frac{+}{-}\frac{1}{2}.

The exclusion principle at once tells us that there may be only two unique sets of these quantum numbers:

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6 0
2 years ago
If 3.6 g of aluminum completely reacts, how much Al2O3 (in grams) can be produced
marissa [1.9K]

The amount in grams of  Al₂O₃ produced is approximately 6.80 g.

Aluminium reacts completely with oxygen(air) to produce Al₂O₃. The reaction can be represented with a chemical equation as follows:

AL + O₂ → Al₂O₃

Let's balance it

4AL + 3O₂ → 2Al₂O₃

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Atomic mass of AL = 27 g

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4(27 g) of AL gives 2(101.96 g) of  Al₂O₃

3.6 g of AL will give ?

cross multiply

mass of  Al₂O₃ produced = 3.6 × 203.92 / 108   = 734.112 / 108 = 6.797

mass of  Al₂O₃ produced = 6.80 g.

read more: brainly.com/question/23982245?referrer=searchResults

8 0
2 years ago
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