Answer:
False; An oxidation-reduction is any chemical process that involves any chemical process in which elements undergo changes in oxidation number. hope that helps love!
Answer: Glucose is an example of carbon-based macromolecule known as carbohydrates
Explanation:
carbon based macromolecule are important cellular components and they perform a variety of functions necessary for growth and development of living organisms. There are 4 major types of carbon based molecules and these includes;
Carbohydrate
Lipids
Proteins and
Nucleic acids.
Carbon is the primary components of these macromolecules. Carbohydrate macromolecules are made up of monosaccharide, disaccharide and polysaccharides. Glucose is an example of a monosaccharide and it has two important types of functional groups: a carbonyl group and a hydroxyl group. I hope this helps. Thanks
Answer:
Beyond the centre of curvature
Explanation:
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Answer:</h3>
9,729.73 L
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Explanation:</h3>
- Based on Boyle's law when temperature is held constant then the volume of a fixed mass of a gas, V is inversely proportional to Pressure, P.
- That is; Pα 1/V
- Mathematically, P= k/V where k is a constant
- Therefore, when the volume of a gas and the pressure are altered,
- P1V1=P2V2 = k, where P1 and P2 are the initial and final pressure respectively while V1 and V2 are the initial and final pressure respectively.
In this case;
Initial Pressure, P1 = 150 atm
Initial volume, V1 = 60.0 L
Final pressure, P2 = 0.925 atm
we are required to calculate the final volume
But, P1V1 =P2V2
Rearranging the formula, V2 = P1V1 ÷ P2
Thus;
V2 =(150 atm × 60.0 L) ÷ 0.925 atm
= 9,729.73 L
The new volume will be 9,729.73 L