X2 +5x+1 x 3x2 - 2x + 4
1 answer:
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Answer:
A) 20+0.6
B) range is [0, 50] (i.e. both inclusive)
C) 8.33 litres
Step-by-step explanation:
Given that concentration of acid in 50 litre container is 40%.
Amount of acid in the container = 40% of 50 litres
Amount of acid in the container =
litres are removed.
Amount of acid removed = 40% of litre.
Now, remaining acid in the container = (20 - 40% of ) litre
Now, replaced with 100% acid.
So, final acid in the container = (20 - 40% of + 100% of
) litre
Amount of acid in the final mixture:
Answer A) Amount of acid in the final mixture = 20+0.6
Answer B) can not be greater than 50 litres (initial volume of container) and can not be lesser than 0 litres.
so, range is [0, 50] (i.e. both inclusive)
Answer C)
Given that final mixture is 50% acid.
amount of acid = 50% of 50 litres = 25 litres
Using the equation: