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Elza [17]
2 years ago
9

PLZZZZ HELP What is the slope of a line that is perpendicular to a line whose equation is 3y=−4x+2 ?

Mathematics
1 answer:
earnstyle [38]2 years ago
6 0

\bf 3y=-4x+2\implies y=\cfrac{-4x+2}{3} \\\\\\ y=\stackrel{\stackrel{slope}{\downarrow }}{-\cfrac{4}{3}}x+\cfrac{2}{3}\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}


so the slope of that line above is really -4/3, now


\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{4}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{3}{4}}\qquad \stackrel{negative~reciprocal}{+\cfrac{3}{4}\implies \blacktriangleright \cfrac{3}{4} \blacktriangleleft}}

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=
Liula [17]

\sqrt{((-6)-(-5))^2 +(9-2)^2}=5\sqrt{2} \approx 7.071

8 0
1 year ago
A baby is weighed on a defective scale. He weighed 13 pounds. The baby weighs exactly 10 pounds. What is the percent error?
Eva8 [605]

Answer:

30%

Step-by-step explanation:

The answer is off by 30%, as the scale is off by 3 pounds. 3/10=30

4 0
2 years ago
Suppose that the population of deer in a state is 1,500 and is growing 2% each year. Predict the population after 4 years.
frutty [35]
Required number
= 1500*(1+2%)^4
=1624(cor.to.the nearest integer)
7 0
2 years ago
Find the area of the shaded region. Express your answer in terms of pi
Likurg_2 [28]

Area of the shaded region is 540 – 65.25π.    

Solution:

Length of the rectangle = 12 + 9 + 6 + 3 = 30 in

Width of the rectangle = 18 in

Radius of the larger circle (r_1) = 12 ÷ 2 = 6 in

Radius of the medium circle (r_2) = 9 ÷ 2 = 4.5 in

Radius of the smaller circle (r_3) = 6 ÷ 2 = 3 in

Area of the shaded region = Area of the rectangle – Area of the larger circle – Area of the medium circle – Area of the smaller circle

                                   =l\times b-\pi r_1^2-\pi r_2^2-\pi r_3^2

                                   =30\times 18-\pi \times 6^2-\pi \times (4.5)^2-\pi \times 3^2

                                   =540-36\pi-20.25\pi-9\pi

                                   =540-65.25\pi

Area of the shaded region is 540 – 65.25π.    

4 0
2 years ago
How do I isolate the “I” variable
hjlf

Answer:

I = \pm \sqrt{\dfrac{P}{R}}

Step-by-step explanation:

P = I^2R

Divide both sides by R.

\dfrac{P}{R} = I^2

Switch sides.

I^2 = \dfrac{P}{R}

Take the square root of both sides.

I = \pm \sqrt{\dfrac{P}{R}}

6 0
2 years ago
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