Please help I'm confused
2 answers:
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Answer:
The 99% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).
Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.
Step-by-step explanation:
Confidence Interval for the proportion:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
For this problem, we have that:
99% confidence level
So , z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
For the percentage:
Multiplying the proportions by 100.
The 99% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).
Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.
Answer:
0.5
Step-by-step explanation:
The given ordered pairs are: (1,2) (2,2.5) (3,3) (4,3.5) (5,4)
The corresponding sequence is :
2,2.5,3,3.5, 4,....
We can see that there is a common difference of d=0.5.
Better still we could use the slope formula:
We substitute the point (1,2) and (2,2.5).
The rate of change of this sequence is: