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Burka [1]
3 years ago
15

A sandwich shop uses the box size shown to pack boxed lunches. They have determined that they need to use bigger boxes. If the s

ide lengths of the square faces are changed to 7 inches, by how much will this increase the volume of the box?

Mathematics
2 answers:
Sonbull [250]3 years ago
8 0

Answer:

240 cubic cm

Step-by-step explanation:

Volume of the box before increament in sides = length*width*height

Length= 5 in.

Width=5 in.

Height = 10 in.

Putting these vales in formula

Volume of box = 5*5*10

                        =250cm^{3}

Now  If the side lengths of the square faces are changed to 7 inches,

So, Length will be 7 in.

Width will be 7 in.

So, new volume = 7*7*10

                          =490cm^{3}

Thus increase in volume = 490-250 =240

Hence by 240 cubic cm  will this increase the volume of the box

borishaifa [10]3 years ago
7 0
The original volume of the shape was 250. You come up with this by multiplying all sides together. So, 5x5x10=250.

We do the same for the new shape, which now has a 7 in place of the 5. So 7x7x10=490.

Lastly, we subtract the volume of the new shape from the volume of the old shape to see the difference. So, 490-250=240.

So the answer to this is 240.
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3 years ago
The coordinate bridge shows the cost of different numbers of bookmarks how many sense do for bookmarks cost.
pogonyaev

Answer:

54 cents

Step-by-step explanation:

The cost of bookmarks relating to the number of bookmarks is given by the graph shown. Therefore:

From the graph, we can determine the relationship between the cost of bookmarks and the number of bookmarks by using two points. The equation of a line passing through points (x_1,y_1)\ and\ (x_2,y_2) is:

y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\

From the graph, y represents the cost of bookmarks in cents and x represent the number of bookmarks. we can see that it passes through the point (2, 30) and (7, 90). Hence:

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7 0
3 years ago
The diagonals of rhombus fghj intersect at point k. if side gh is equal to 3x - 10 and side jh is equal to 6x - 19, find x
exis [7]
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1) Subtract 3x from both sides.

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2) Add 19 to both sides.

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3) Divide both sides by 3.

3 = x

x =3.
8 0
2 years ago
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