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Oduvanchick [21]
3 years ago
10

How much heat is required to raise the temperature of 88.5 g of water from its melting point to its boiling point?

Chemistry
1 answer:
k0ka [10]3 years ago
5 0
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Which law states that the volume of a gas is proportional to the moles of the gas when pressure and temperature are kept constan
Phoenix [80]
<span>Boyles law states that the volume of a gas is proportional to the moles of the gas when pressure and temperature are kept constant.    </span>
3 0
3 years ago
Read 2 more answers
Which of the following is the best piece of laboratory glassware for preparing 500.0 mL of an aqueous solution of a solid?
Leni [432]

Answer:

The correct answer is option A.

Explanation:

Volumetric flask  : A glass ware with round lower body with flat bottom and with thin cylindrical neck along with mark which indicates the specific volume filled to that mark.It is used in preparation of standard solution of compound with desired concentration with fixed volume.

Erlenmeyer flask : is a flask with conical shape with flat bottom used in titration  experiments to carry out reaction with fixed volume of solution.

Test tube : Small cylindrical tube with rounded bottom used to observe reaction in between reactant taken in small amount.

Graduated beaker : Laboratory glassware used measure larger volumes of solution or to mix or stir solutions and liquids.

Graduated cylinder : Laboratory thin cylindrical glassware with accurate marking of volume used to measure an accurate volume of solutions or liquids required in an experiment.

<em><u>Volumetric flask</u></em> is the best piece of laboratory glassware for preparing 500.0 mL of an aqueous solution of a solid

8 0
2 years ago
Read 2 more answers
Se hace reaccionar 4,00 g de aluminio y 42,00 g de bromo, según la reacción: Al(s)+Br2(l)⟶AlBr3(s) Calcular las moles de AlBr3(s
NeX [460]

Answer:

0.145 moles de AlBr3.

Explanation:

¡Hola!

En este caso, al considerar la reacción química dada:

Al(s)+Br2(l)⟶AlBr3(s)

Es claro que primero debemos balancearla como se muestra a continuación:

2Al(s)+3Br2(l)⟶2AlBr3(s)

Así, calculamos las moles del producto AlBr3 por medio de las masas de ambos reactivos, con el fin de decidir el resultado correcto:

n_{AlBr_3}^{por\ Al}=4.00gAl*\frac{1molAl}{27gAl} *\frac{2molAlBr_3}{2molAl}=0.145mol AlBr_3\\\\n_{AlBr_3}^{por\ Br_2}=42.00gr*\frac{1molr}{160g Br_2} *\frac{2molAlBr_3}{3molBr_2}=0.175mol AlBr_3

Así, inferimos que el valor correcto es 0.145 moles de AlBr3, dado que viene del reactivo límite que es el aluminio.

¡Saludos!

3 0
2 years ago
Two closed vessels contain chlorine gas at the same conditions of temperature and
wariber [46]

Answer:12 mol

Explanation: both vessels are at the same temp and pressure (and the pressure is low and/or the temperature high).

6.7mol per 1.3L = 6.7/1.3 mol/L

so in 2.33L = 6.7*2.33/1.3 = 12 mol

8 0
2 years ago
What is the role of plastocyanin in the z-scheme model?
murzikaleks [220]

Answer:

It shuttles electrons between the cytochrome complex and photosystem I.

Explanation:

6 0
2 years ago
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