The molarity of Sr(OH)2 solution is = 0.1159 M
calculation
write the equation for reaction
that is, Sr(OH)2 +2HCl→ SrCl2 + 2 H2O
then finds the mole of HCl used
moles = molarity x volume
=40.03 x0.1159 = 4.639 moles
by use of mole ratio between Sr(OH)2 to HCL which is 1 :2 the moles of Sr(OH)2 is therefore = 4.639 x1/2 = 2.312 moles
molarity of Sr(OH)2 is = moles / volume
=2.312 /20 =0.1159 M
Ethane
see the picture for explanation
Answer:
The correct options are: Z1) They tend to form cations, and Z4) They tend to form ionic compounds when they combine with the elements of Group VIIA.
Explanation:
The chemical elements that have a tendency of <u>losing their valence electrons</u> and are generally present on the <u>left-side of the periodic table</u> are known as metals.
The general characteristics of metals are malleability, ductility, lustre, high thermal and electrical conductivity.
The metals<u> readily lose their valence electrons</u> present in their valence electron shell to<u> form positively charged ions called </u><u>cation</u>s and thus have <u>low ionization energy</u>.
They also tend to form<u> </u><u>ionic compounds or salts</u><u> </u>with the <u>reactive non-metals belonging to the Group VIIA of the periodic table.</u>
<u>Therefore, </u><u>Z1 and Z4 </u><u>are the properties of most metals.</u>
The rheo leaf peel will lose water by osmosis and become flaccid. If the rheo leaf was boiled, this would not happen.
<h3>What is osmosis?</h3>
Across living membranes, water moves from a region of high to a region of low water potential.
Concentrated sugar solutions have low water potential when compared to the cell sap of the cells of rheo leaf peel. Thus, water will move from the rheo leaf peel to the sugar solution.
This will result in the wilting of the leaf peel.
If the leaf peel is boiled, the membranes in the cells die and can no longer function as a selectively permeable interface.
More on osmosis can be found here: brainly.com/question/1799974
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