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scZoUnD [109]
3 years ago
7

The bathroom mirror has water droplets on it after a hot shower. choose the correct phase change. HELPP

Chemistry
1 answer:
Liula [17]3 years ago
6 0

Answer:

what?

Explanation:

what the hell?

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This graph shows two curves pertaining to a hydrogen s orbital.
fgiga [73]

Answer 1) : According to the complete question attached in the answer,

The radial wave function  which is denoted by R_{nl}(r) shown with orange color crosses through zero point. Also, At the the radial nodes, which are spherical shells to some radial distance away from the nucleus there no electron are found.

Also, the radial probability distribution curve denoted as R^{2}_{nl}(r) shown in  blue  color is observed to touch zero, and shows the place of radial node.

Therefore, the total number of nodes will include both the kinds  which has radial and angular nodes which will be represented by <em>'n'</em>.

It is observed that for any atomic orbital, the total number of nodes will be n-1  .


Considering the s orbital of the hydrogen, which has zero angular momentum  (l); (l=0), as it has zero angular nodes.  

Hence, there will be only radial nodes, which is

(n−1  =  total number of radial nodes in s orbitals)

According to the image, there are 4  radial nodes shown, so n  =  5  (as n-1 = 4; therefore, n = 5)

This represents the 5s orbital.


Answer 2) The radial nodes are observed in I'm seeing radial nodes at  

1.9a_{0},  6.4a_{0},13.9a_{0} and  27.0a_{0}.

where  a_{0} represents the  hydorgen bohr atomic radius =  0.0529177 nm


Explanation : It is quite easy to observe the given graph and find out the approximate values of the radial nodes, it does not requires any equation to be solved. Equation can be used to find the radial nodes if it was supplied along with the question. Although by mere speculation one can find out the answer.

3 0
3 years ago
Read 2 more answers
Which mixture is heterogeneous
scZoUnD [109]

Answer:

A

Explanation:

4 0
3 years ago
Why are elements with high electron affinities also the most electronegative?
melamori03 [73]

Explanation:

Electron affinity is the energy released in adding an electron to a neutral atom in the gas phase. This is a measure of the readiness of an atom to gain an electron. When an atom gains an electron readily, it has a high electron affinity.

  • The electronegativity is a property that combines the ability of its atom to lose and gain electrons.
  • It is expressed as a number that describes the relative tendency with which the atoms of the element attracts valence electrons in a chemical bond.

Therefore , we see that an atom with a high electronegativity will have a very high affinity to gain electrons. It will want to attract electrons by all means to itself.

Learn more:

Electronegativity brainly.com/question/11932624

#learnwithBrainly

7 0
4 years ago
Write the balanced COMPLETE ionic equation for the reaction when Cs3PO, and AgNO3 are mixed in aqueous solution. If no reaction
OLEGan [10]

Answer:help

Explanation:

3 0
3 years ago
A multi-nutrient fertilizer contains several different nitrogen containing compounds. The fertilizer is 54.8% CH4N2O (urea), 26.
vesna_86 [32]

Answer:

  • <u><em>9.01 g of fertilizer</em></u>

Explanation:

Assume initially that the amount in grams of the multinutrient fertilizer is 100 g, and calculate the amount of nitrogen supplied by every compound present in these 100 g of fertilizer.

<u>1) Urea (CH₄N₂O)</u>:

  • Molar mass of urea: 60.06 g/mol
  • Atomic mass of N: 14.007 g/mol
  • Total mass of N in the formula: 2 × 14.007 g/mol = 28.014 g/mol
  • Amount of N in 100 g of compound: 100 g × 54.8% × 28.014 g / 60.06 g =  25.56 g

<u>2) KNO₃</u>

  • Molar mass of KNO₃: 101.1032 g/mol
  • Atomic mass of N: 14.007 g/ mol
  • Total mass of N in the formula: 14.007 g/mol
  • Amount of N in 100 of the compound: 100 g × 26.3% × 14.007 / 101.1032 = 3.64 g

<u>3) (NH₄)₂PO₄</u>

  • Molar mass of (NH₄)₂PO₄: 132.06 g/mol
  • Atomic mass of N: 14.007 g/ mol
  • Total mass of N in the formula: 2×14.007 g/mol = 28.014 g/mol
  • Amount of N in 100 of the compound: 100 g × 14.1% × 14.007 / 132.06 = 2.99 g

4) <u>Total mass of N in 100 g of fertilizer</u>:

Add all the amounts of N obtained above

  • 25.56g + 3.69 g + 2.99 g = 32.19 g of N

5) <u>Mass of fertilizer that should be applied to provide 2.90 g of N to a plant</u>.

Set a proportion:

  • 32.19 g of N / 100 g of fertilizer = 2.90 g of N / X

Solve for X:

  • X = 2.90 g of N × 100 g of fertilizer / 32.19 g of N = 9.01 g of fertilizer

That is the answer: 9.01 g of fertilizer should be applied to provide 2.90g  of N to a plant.

4 0
3 years ago
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