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3 years ago

8. In some reactions the process of oxidation and reduction takes place simultaneously. What are these

Chemistry

1 answer:

antoniya [11.8K]3 years ago

4 0

Answer:

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Explanation:

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element that is neither a non-metal nor a metalloid, and is characterized by thin, dark grey filaments exhibiting magnetic prope

Digiron [165]

Yes would you explain better

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4 years ago

Which statement accurately describes what happens when water turns to stream in terms of energy?

-Dominant- [34]

When water turns to steam,

D) the water absorbs energy which causes the water molecules to have more kinetic and potential energy changing their configuration from a liquid to a gas.

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3 years ago

Read 2 more answers

The diagram below shows the different phase transitions that occur in matter.

solmaris [256]

Answer:

# 5

Explanation:

The question describes silver being "poured" into a mold and cools to become a solid bar. This is the phase of liquid to solid. When a element cools down below it's freezing points to become a solid.

Liquid to Solid Definition:

Freezing, or solidification, is a phase transition in which a liquid turns into a solid when its temperature is lowered to or below its freezing point. All known liquids, except helium, freeze when the temperature is low enough.

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2 years ago

A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som

jek_recluse [69]

The question is incomplete, the complete question is:

A certain substance X has a normal freezing point of $-6.4^oC$ and a molal freezing point depression constant $K_f=3.96^oC.kg/mol$ . A solution is prepared by dissolving some glycine in 950. g of X. This solution freezes at $-13.6^oC$ . Calculate the mass of urea that was dissolved. Round your answer to 2 significant digits.

Answer: The mass of glycine that can be dissolved is $1.3\times 10^2g$

Explanation:

Depression in the freezing point is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution.

The expression for the calculation of depression in freezing point is:

$\text{Freezing point of pure solvent}-\text{freezing point of solution}=i\times K_f\times m$

$\text{Freezing point of pure solvent}=\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}}$ ......(1)

where,

Freezing point of pure solvent = $-6.4^oC$

Freezing point of solution = $-13.6^oC$

i = Vant Hoff factor = 1 (for non-electrolytes)

$K_f$ = freezing point depression constant = $3.96^oC/m$

$m_{solute}$ = Given mass of solute (glycine) = ?

$M_{solute}$ = Molar mass of solute (glycine) = 75.07 g/mol

$w_{solvent}$ = Mass of solvent = 950. g

Putting values in equation 1, we get:

$-6.4-(-13.6)=1\times 3.96\times \frac{m_{solute}\times 1000}{75.07\times 950}\\\\m_{solute}=\frac{7.2\times 75.07\times 950}{1\times 3.96\times 1000}\\\\m_{solute}=129.66g=1.3\times 10^2g$

Hence, the mass of glycine that can be dissolved is $1.3\times 10^2g$

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3 years ago

A car is traveling with velocity of 40 m/s and has a mass of 1120 kg. The car has __________ energy.

Nata [24]

Answer:

Explanation:

The car has kinetic energy.

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3 years ago